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mylen [45]
4 years ago
12

List four greenhouse gases in the atmosphere. For each gas, describe its prevalence in the atmosphere, its natural sources, its

human-induced sources, and how its concentration in the atmosphere might be changing.
Chemistry
1 answer:
lukranit [14]4 years ago
5 0

Answer:

Fossil fuels, carbon dioxide, gases released from polluted waste, and gases released in the air that are trapped in our atmosphere

Explanation:

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Find and fix each mistake in the following equilibrium constant expressions.
IRINA_888 [86]

Answer:

A. c. Keq=[H2]^2[S2]/[H2S]^2

B. b. Keq=[COCl2]/[CO][Cl2]

Explanation:

Hello,

In this case, considering the law of mass action which states that the equilibrium expression is written in terms of the concentration of products divided by the concentration of reactants considering the stoichiometric coefficients as powers we obtain:

A. For the reaction:

2H_2S(g)\rightleftharpoons 2H_2(g)+S_2(g)

The equilibrium expression is:

Keq=\frac{[H_2]^2[S_2]}{[H_2S]^2}

Therefore, answer is c. Keq=[H2]^2[S2]/[H2S]^2.

B. For the reaction:

CO(g)+Cl_2(g)\rightleftharpoons COCl_2(g)

The equilibrium expression is:

Keq=\frac{[COCl_2]}{[CO][Cl_2]}

Therefore, answer is b. Keq=[COCl2]/[CO][Cl2].

Regards.

8 0
3 years ago
How many grams of carbon dioxide will be produced if 76.4 grams of
goldfiish [28.3K]

Answer:

Assuming that all of the oxygen is used up, 1.53×4111.53×411 or 0.556 moles of C2H3Br3 are required. Because there are only 0.286 moles of C2H3Br3 available, C2H3Br3 is the limiting reagent.

Limiting Reagent What is the limiting reagent if 76.4 grams of C2H3Br3 were reacted with 49.1 grams of O2? C2H3Br3 + 11O2 → 8CO2 + 6H2O + 6Br2 SOLUTION Using Approach 1: A. 76.4g × (1 mol/ 266.72 g) = 0.286 moles C2H3Br3 49.1g × (1 mole/ 32 g) = 1.53 moles O2 B.

Explanation:

MRK ME BRAINLIEST PLZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZ

https://chem.libretexts.org/Bookshelves/Introductory_Chemistry/Map%3A_Introductory_Chemistry_(Tro)/08%3A_Quantities_in_Chemical_Reactions/8.04%3A_Limiting_Reactant_and_Theoretical_Yield

5 0
3 years ago
Calculate the mass percent of carbon (c) in carbon tetrachloride, (ccl4), if the molar mass of carbon tetrachloride is 153.8g.
baherus [9]
<span>mass percent of carbon (c) in CCl</span>₄ = mass of C/mass of CCl₄
                                                        = 12 x 100/153.8 = 7.8%


3 0
3 years ago
Read 2 more answers
Help help help !!!!!!
11111nata11111 [884]

Answer:

3. 116.5 V

4. 119.6 V

Explanation:

3. Determination of the voltage.

Resistance (R) = 25 Ω

Current (I) = 4.66 A

Voltage (V) =?

V = IR

V = 4.66 × 25

V = 116.5 V

Thus, the voltage is 116.5 V

4. Determination of the voltage.

Current (I) = 9.80 A

Resistance (R) = 12.2 Ω

Voltage (V) =?

V = IR

V = 9.80 × 12.2

V = 119.6 V

Thus, the voltage is 119.6 V

4 0
3 years ago
Why does liquid water have such a high specific heat value compared to
harina [27]

Answer:

Water Capacity

Explanation:

Water's high heat capacity is a property caused by hydrogen bonding among water molecules. When heat is absorbed, hydrogen bonds are broken and water molecules can move freely. When the temperature of water decreases, the hydrogen bonds are formed and release a considerable amount of energy.

Hope this helps !

7 0
3 years ago
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