1. D
2. D
3. c
4. A
5. C
I'm not 100% sure about these. Just letting you know.
Complete Question
A dog weighs 2 pounds less than 3 times the weight of a cat. The dog weighs twenty two more pounds than the cat.
Write and solve an equation to find the weights of the cat and the dog.
Answer:
Weight of cat = x = 12 pounds
Weight of Dog = y = 34 pounds
Step-by-step explanation:
Let's represent:
Weight of cat = x
Weight of Dog = y
A dog weighs 2 pounds less than 3 times the weight of a cat.
y = 3x - 2........ Equation 1
The dog weighs twenty two more pounds than the cat
y = x + 22....... Equation 2
The equation is given as:
y = y
3x - 2 = x + 22
Collect like terms
3x - x = 22 + 2
2x = 24
x = 24/2
x = 12 pounds
Solving for y using any of the equations:
y = 3x - 2
y = 3 × 12 - 2
y = 36 - 2
y = 34 pounds
Therefore:
Weight of cat = x = 12 pounds
Weight of Dog = y = 34 pounds
Answer: 153.56
Step-by-step explanation:
Hi, to answer this question we have to apply the next formulas:
Volume of a cone: 1/3 π r² h
Where r is the radius and h is the height (unknown)
Diameter = r x 2
8 = 2r
8/2 =r
r = 4
Before calculating the volume we have to apply the Pythagorean Theorem to find h. (where the slant is the hypotenuse and h and r are the sides of the triangle)
10 ² = h² + 4²
Solving for h
100 = h² + 16
100-16 = h²
84= h²
√84 =h
9.16= h
Back on the volume formula:
V= 1/3 π r² h
V =1/3 π 4² (9.16) =153.56
log was used calculate big numbers before calculators
log is a re-arranged way to show a number with an exponent
example
log₂ 16 = 4 means 2^4 = 16
logx(Z) = y means x^y=Z
log(x-6)/log(2) + log(x)/log(2) = 4
(log(x-6)+ log(x))/log(2) = 4
(log(x-6)+ log(x)) = 4log(2)
(log(x-6)x) = log(16)
x=8
Answer:4.36?
Step-by-step explanation:
distance or area?
A=lw
48=11L
4.36=l
