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Arturiano [62]
3 years ago
8

From 10 men and 8 women in a pool of potential jurors, 12 people are chosen at random to constitute a jury. Suppose that you obs

erve the number of men who are chose for the jury. Let A be the event that at least half of the 12 jurors are men and B be the event that at least half of the 8 women are on the jury.
(a) Determine the sample space of this random experiment.
(b) Find A B, A B, and A B? listing the outcomes for each of those three events.
(c) Are A and B mutually exclusive? (explain your answer) (d) Are A and B? mutually exclusive?(explain your answer)
(e) Are A? and B? mutually exclusive?(explain your answer
Mathematics
1 answer:
Nikitich [7]3 years ago
8 0
I think it’s C
I hope that help
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I can’t find this answer, help me plss
Vinvika [58]

2) 7/4×(22–x) =0

soln

= 7/4×(22 –x) =0

= 1.75 ×22 –x =0

= x=38.5

9) 15x² /7 =8x²/5

soln

= 15x²×8x²=7×5

=120x^4 = 35

= x^4 =120–35

x^4 =85

6) 9x²/4–4=0

soln

=9x²/4–4=0

=2.25–4=0

=4–2.25=0

=1.75

<h2><em>sorry </em><em>I </em><em>know </em><em>that </em><em>much </em></h2>
8 0
3 years ago
For a certain model of car the distance d required to stop the vehicle if it is traveling at v mi/h is given by the formula d =
enyata [817]
Given that <span>For a certain model of car the distance d required to stop the vehicle if it is traveling at v mi/h is given by the formula d=v+\frac{v^2}{20}, where [tex]d is measured in feet.

If Kerry wants her stopping distance not to exceed 75 ft, then the range of speeds (in mi/h) can she travel is obtained as follows:

v+ \frac{v^2}{20} \leq75 \\  \\ 20v+v^2\leq1,500 \\  \\ v^2+20v+100\leq1,500+100 \\  \\ (v+10)^2\leq1,600 \\  \\ |v+10|\leq\sqrt{1,600} \\  \\ -40\leq v+10\leq40 \\  \\ -40-10\leqv\leq v\leq40-10 \\  \\ -50\leq v\leq30

Therefore, the range of speed she can travel is v\leq30\ mi/hr
</span>
8 0
3 years ago
What is the approximate area of the shaded sector in the circle shown below
Novay_Z [31]

Answer:

please provide the diagram

3 0
2 years ago
Read 2 more answers
The endpoints of EF<br> are E(1,3) and F(-2,8).<br> Find EF.
Phantasy [73]

Answer:

EF = \sqrt{34} ≈ 5.83

Step-by-step explanation:

Calculate EF using the distance formula

d = \sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2    }

with (x₁, y₁ ) = E(1, 3) and (x₂, y₂ ) = F(- 2, 8)

EF = \sqrt{(-2-1)^2+(8-3)^2}

    = \sqrt{(-3)^2+5^2}

    = \sqrt{9+25}

    = \sqrt{34} ≈ 5.83 ( to 2 dec. places )

8 0
3 years ago
Y is directly related to x and y is 81 when x is 27 the constant of.variation is
suter [353]

Answer:

The constant of variation is 3

Step-by-step explanation:

Given.

y=81

x=27

And y is directly related to x

y ∝ x

Here k is constant of variation

y=kx

k=\frac{y}{x}--------------(1)

Put the y and x value in equation 1.

k=\frac{81}{27}

k=3

So, the constant of variation is 3.

6 0
3 years ago
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