Given that <span>For
a certain model of car the distance

required to stop the vehicle if
it is traveling at

mi/h is given by the formula
![d=v+\frac{v^2}{20}, where [tex]d](https://tex.z-dn.net/?f=d%3Dv%2B%5Cfrac%7Bv%5E2%7D%7B20%7D%2C%20where%20%5Btex%5Dd%20)
is measured in feet.
If Kerry wants her stopping distance not to exceed 75
ft, then the range of speeds (in mi/h) can she travel is obtained as follows:

Therefore, the range of speed she can travel is

</span>
Answer:
please provide the diagram
Answer:
EF =
≈ 5.83
Step-by-step explanation:
Calculate EF using the distance formula
d = 
with (x₁, y₁ ) = E(1, 3) and (x₂, y₂ ) = F(- 2, 8)
EF = 
= 
= 
=
≈ 5.83 ( to 2 dec. places )
Answer:
The constant of variation is 3
Step-by-step explanation:
Given.


And y is directly related to x
∝ 
Here k is constant of variation

--------------(1)
Put the
and
value in equation 1.


So, the constant of variation is 3.