Selling price of app per user = $10 per month
Total no. of user in first month = 10
To tal no. of user added per month = 7
We have to find how much money is earned in one year
So the formula is n/2 * (2a +(n-1)d)
Here we have n = 12 which is total no. of months
a = 100 , which is money earned in one month
d = 70 , which is increase in money earned per month
So money earned in a year comes out to be 5820
Answer:
Check the explanation
Step-by-step explanation:
Following table shows the calculations:
Delta, X Southwest , Y X^2 Y^2 XY
45.96 38.76 2112.3216 1502.3376 1781.4096
46.8 45.41 2190.24 2062.0681 2125.188
47.93 15.7 2297.2849 246.49 752.501
51.78 49.58 2681.1684 2458.1764 2567.2524
52.17 44.34 2721.7089 1966.0356 2313.2178
47.36 18 2242.9696 324 852.48
Total 292 211.79 14245.6934 8559.1077 10392.0488
Sample size: n =6
Now
![S_{yy}=\sum y^{2}-\frac{\left (\sum y \right )^{2}}{n}=1083.27](https://tex.z-dn.net/?f=S_%7Byy%7D%3D%5Csum%20y%5E%7B2%7D-%5Cfrac%7B%5Cleft%20%28%5Csum%20y%20%5Cright%20%29%5E%7B2%7D%7D%7Bn%7D%3D1083.27)
![S_{xx}=\sum x^{2}-\frac{\left (\sum x \right )^{2}}{n}=35.03](https://tex.z-dn.net/?f=S_%7Bxx%7D%3D%5Csum%20x%5E%7B2%7D-%5Cfrac%7B%5Cleft%20%28%5Csum%20x%20%5Cright%20%29%5E%7B2%7D%7D%7Bn%7D%3D35.03)
![S_{xy}=\sum xy-\frac{\left (\sum x \right )\left (\sum y \right )}{n}=84.94](https://tex.z-dn.net/?f=S_%7Bxy%7D%3D%5Csum%20xy-%5Cfrac%7B%5Cleft%20%28%5Csum%20x%20%5Cright%20%29%5Cleft%20%28%5Csum%20y%20%5Cright%20%29%7D%7Bn%7D%3D84.94)
The coefficient of correlation is :
![r=\frac{S_{xy}}{\sqrt{S_{xx}S_{yy}}}=0.436](https://tex.z-dn.net/?f=r%3D%5Cfrac%7BS_%7Bxy%7D%7D%7B%5Csqrt%7BS_%7Bxx%7DS_%7Byy%7D%7D%7D%3D0.436)
Answer:
The correct answer is (x-y)
Step-by-step explanation:
x^2-xy
x(x-y)
Answer:
![40\%](https://tex.z-dn.net/?f=40%5C%25)
Step-by-step explanation:
![\frac{2}{5} \times 100 = 40\%](https://tex.z-dn.net/?f=%20%5Cfrac%7B2%7D%7B5%7D%20%20%5Ctimes%20100%20%3D%2040%5C%25)