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aleksklad [387]
3 years ago
12

A quart of paint covers about 85 square feet. About how many quarts would you need to cover a fence with an area of 3,817 square

feet?
Mathematics
1 answer:
Vikentia [17]3 years ago
6 0

Answer:

you would need 45 quarts of paint

Step-by-step explanation:

if you divide 3,817 by 85 you would get 44.905882 but you need to only use whole number and if you chose 44 you would not have enough so you would round up to 45

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Linda and Rob open an online savings account that has a 2.89% annual interest rate, compounded
sp2606 [1]

Answer:

FV= $34,222.33

Step-by-step explanation:

<u>First, we need to calculate the weekly interest rate:</u>

Weekly interest rate= 0.0289/52= 0.00056

<u>To calculate the future value (FV), we need to use the following formula:</u>

FV= {A*[(1+i)^n-1]}/i

A= weekly deposit

n= 15*52= 780

A= $35

FV= {35*[(1.00056^780) - 1]} / 0.00056

FV= $34,222.33

4 0
2 years ago
What is the measure of AC⏜ ?
Gre4nikov [31]

Answer:

41

Step-by-step explanation:

5 0
3 years ago
Find the volume of the solid generated when R​ (shaded region) is revolved about the given line. x=6−3sec y​, x=6​, y= π 3​, and
Dmitrij [34]

Answer:

V=9\pi\sqrt{3}

Step-by-step explanation:

In order to solve this problem we must start by graphing the given function and finding the differential area we will use to set our integral up. (See attached picture).

The formula we will use for this problem is the following:

V=\int\limits^b_a {\pi r^{2}} \, dy

where:

r=6-(6-3 sec(y))

r=3 sec(y)

a=0

b=\frac{\pi}{3}

so the volume becomes:

V=\int\limits^\frac{\pi}{3}_0 {\pi (3 sec(y))^{2}} \, dy

This can be simplified to:

V=\int\limits^\frac{\pi}{3}_0 {9\pi sec^{2}(y)} \, dy

and the integral can be rewritten like this:

V=9\pi\int\limits^\frac{\pi}{3}_0 {sec^{2}(y)} \, dy

which is a standard integral so we solve it to:

V=9\pi[tan y]\limits^\frac{\pi}{3}_0

so we get:

V=9\pi[tan \frac{\pi}{3} - tan 0]

which yields:

V=9\pi\sqrt{3}]

6 0
3 years ago
I WILL MARK YOU THE BRAINLIEST IF YOU ANSWER THIS CORRECTLY WITH WORK
saul85 [17]

Answer:

Students on Honor Roll had no advantage to get the Science class requested. It was a fair class assignment. In fact No Honor Roll students had advantage over honor Roll Students in obtaining Science Class as requested.  

Step-by-step explanation:

Here let us streamline the information we are given one by one

1.) Honor Roll

Get Requested Science Class                : 64

Did Not get  Requested Science Class : 80

Total                                                         : 144

Percentage of Honor Roll Students getting Science class as requested =

\frac{64}{144}

= 44.44%

2.) No Honor Roll

Get Requested Science Class               : 315

Did Not get Requested Science Class :  41

Total                                                         : 356

Percentage of Non Honor Roll Students getting Science class as requested = \frac{315}{356}

= 88.8%

By observing the above result , we can assume that Honor Roll students did not have any advantage over non Honor Roll students in getting Science Class as they requested.

3 0
3 years ago
A high school coach wants to buy new shirts for the 25 members of the track team. The coach must spend less than $300 on the shi
aksik [14]
25 less than or equal too 300,not really enough information
3 0
3 years ago
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