Answer:
3 long tails : 1 short tail
Explanation:
This question involves a single gene coding for tail length in mice. The allele for long tail (T) is dominant over the allele for short tail (t). This means that an heterozygous mice will possess the long tail length.
According to this question, in a cross between two hybrid or heterozygote mice i.e. Tt × Tt, the following gametes will be produced by each parent:
Tt - T and t
Using these gametes in a punnet square (see attached image), the following will be produced: TT, Tt, Tt and tt.
Offsprings with genotype TT, Tt and Tt will have a LONG TAIL while genotype tt will have a SHORT TAIL. Hence, the phenotypic ratio will be 3 long tails : 1 short tail.
Answer:
n a population, more individuals are born than can survive. The available resources in nature are finite (food, water, space, etc.) and the environment is not able to support unlimited growth of a population. This causes an inevitable struggle for existence among individuals (continual struggle for existence).Explanation:
Answer:
2 NH3 (ammonia) + CO2 + 3 ATP + H2O → H2N-CO-NH2 (urea) + 2 ADP + 4 Pi + AMP
Explanation:
I found the formula for creating urine innthe body, i think its ammonia that is created by the nitrogen excess abd waste produced by the body.
Hope this helps
Answer:
The correct answer is b. All round seeds
Explanation:
If an RR plant is crossed with an rr plant than all the phenotype will produce round seed and the frequency of the Round seed plant to wrinkled seed plant would be 4:0.
R R
r Rr Rr
r Rr Rr
So all the phenotypes will be heterozygous dominant for the round seed which means that all phenotypes will have a single dominant allele for round seed which is enough to express round seeds in the phenotypes.
Answer:
C. Both parents
Explanation:
I am not going to explain in full detail but basically the offspring needs something from the mom and the dad to live