This question is not that hard but I’m getting rushed
1 answer:
You might be interested in
Answer:
The probability of founding exactly one defective item in the sample is P=0.275.
The mean and variance of defective components in the sample are:
Step-by-step explanation:
In the case we have a lot with 3 defectives components, the proportion of defectives is:
a) The number of defectives components in the 5-components sample will follow a binomial distribution B(5,0.075).
The probability of having one defective in the sample is:
b) The mean and variance of defective components in the sample is:
The Chebyschev's inequality established: