What is the factorization of 49b2 − 81? (7b – 9)(7b – 9) (7b – 9)(7b + 9) (7b2 – 9)(7b2 – 9) (7b2 – 9)(7b2 + 9)

2 answers:

5 0

The factorisation of 49b^2 - 81 is (7b - 9)(7b + 9). This is because 49 and 81 are the squares of 7 and 9 respectively, so these must be multiplied together. b^2 is b x b. Finally, it must be -9 and +9 to make -81, because when the signs are the same the result is a positive number.
Hope this helps.
GOOD LUCK WITH MATH!!!

Naddika [18.5K]3 years ago

5 0

49b^2 − 81 = <span> (7b + 9)(7b – 9)

answer
</span><span>(7b – 9)(7b + 9)</span>

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