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Airida [17]
3 years ago
10

Please answer this it’s due soon

Mathematics
2 answers:
DaniilM [7]3 years ago
6 0

Answer:

Down

Step-by-step explanation:

As the lines of the parabola point down, the parabola opens down.

Kobotan [32]3 years ago
6 0

Answer:

Down

Step-by-step explanation:

When

the lines of the parabola point down, the parabola opens down.

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Find values for θ that make each statement true (show steps)
Ksju [112]

Answer:

Step-by-step explanation:

1. sinФ = cos 25

25 ° is in the between 0 and 90°

therefore it can simply represent

cosФ= sin (90-Ф) = sin (90 - 25) = sin 65

2. sin(Ф/3 + 10) = cos Ф

cos Ф = sin (90 -Ф)

sin(Ф/3 + 10) = cos Ф

sin(Ф/3 + 10) = cos Ф = sin(90-Ф)

Ф/3+10=90-Ф

10Ф+3/30 = 90-Ф

10Ф+3 = 30(90-Ф)

10Ф+3 = 2700-30Ф

10Ф+30Ф=2700-3

40Ф = 2697

Ф = 2697 / 40 = 67.425 ≅ 67.4°

4 0
3 years ago
What is the measure of the central angle of a circle with radius 15ft that intercepts a 10ft arc
svetlana [45]
Radius = 15 feet
circumference = 2 * PI * 15 = <span> <span> <span> 94.25 </span></span></span>feet
the length of the arc is 10 feet
So the angle would equal (10 / 94.25) * 360 = <span> <span> <span> 0.1061007958 </span> </span> </span> * 360 =
=  <span> <span> <span> 38.196</span></span></span> degrees



5 0
3 years ago
Find the indicated term of the given arithmetic sequence. Find the indicated term of the given arithmetic sequence. a^1 = 45, d
Ymorist [56]
An = a1+d*(n-1)
a8 = 45 - 6*(8-1) = 3
7 0
3 years ago
Dr. Miriam Johnson has been teaching accounting for over 20 years. From her experience, she knows that 60% of her students do ho
oksano4ka [1.4K]

Answer:

a) The probability that a student will do homework regularly and also pass the course = P(H n P) = 0.57

b) The probability that a student will neither do homework regularly nor will pass the course = P(H' n P') = 0.12

c) The two events, pass the course and do homework regularly, aren't mutually exclusive. Check Explanation for reasons why.

d) The two events, pass the course and do homework regularly, aren't independent. Check Explanation for reasons why.

Step-by-step explanation:

Let the event that a student does homework regularly be H.

The event that a student passes the course be P.

- 60% of her students do homework regularly

P(H) = 60% = 0.60

- 95% of the students who do their homework regularly generally pass the course

P(P|H) = 95% = 0.95

- She also knows that 85% of her students pass the course.

P(P) = 85% = 0.85

a) The probability that a student will do homework regularly and also pass the course = P(H n P)

The conditional probability of A occurring given that B has occurred, P(A|B), is given as

P(A|B) = P(A n B) ÷ P(B)

And we can write that

P(A n B) = P(A|B) × P(B)

Hence,

P(H n P) = P(P n H) = P(P|H) × P(H) = 0.95 × 0.60 = 0.57

b) The probability that a student will neither do homework regularly nor will pass the course = P(H' n P')

From Sets Theory,

P(H n P') + P(H' n P) + P(H n P) + P(H' n P') = 1

P(H n P) = 0.57 (from (a))

Note also that

P(H) = P(H n P') + P(H n P) (since the events P and P' are mutually exclusive)

0.60 = P(H n P') + 0.57

P(H n P') = 0.60 - 0.57

Also

P(P) = P(H' n P) + P(H n P) (since the events H and H' are mutually exclusive)

0.85 = P(H' n P) + 0.57

P(H' n P) = 0.85 - 0.57 = 0.28

So,

P(H n P') + P(H' n P) + P(H n P) + P(H' n P') = 1

Becomes

0.03 + 0.28 + 0.57 + P(H' n P') = 1

P(H' n P') = 1 - 0.03 - 0.57 - 0.28 = 0.12

c) Are the events "pass the course" and "do homework regularly" mutually exclusive? Explain.

Two events are said to be mutually exclusive if the two events cannot take place at the same time. The mathematical statement used to confirm the mutual exclusivity of two events A and B is that if A and B are mutually exclusive,

P(A n B) = 0.

But, P(H n P) has been calculated to be 0.57, P(H n P) = 0.57 ≠ 0.

Hence, the two events aren't mutually exclusive.

d. Are the events "pass the course" and "do homework regularly" independent? Explain

Two events are said to be independent of the probabilty of one occurring dowant depend on the probability of the other one occurring. It sis proven mathematically that two events A and B are independent when

P(A|B) = P(A)

P(B|A) = P(B)

P(A n B) = P(A) × P(B)

To check if the events pass the course and do homework regularly are mutually exclusive now.

P(P|H) = 0.95

P(P) = 0.85

P(H|P) = P(P n H) ÷ P(P) = 0.57 ÷ 0.85 = 0.671

P(H) = 0.60

P(H n P) = P(P n H)

P(P|H) = 0.95 ≠ 0.85 = P(P)

P(H|P) = 0.671 ≠ 0.60 = P(H)

P(P)×P(H) = 0.85 × 0.60 = 0.51 ≠ 0.57 = P(P n H)

None of the conditions is satisfied, hence, we can conclude that the two events are not independent.

Hope this Helps!!!

7 0
3 years ago
Julie has 4/3 cups of flour.She needs 2/5 cups of flour.How will she get the amount.
valentina_108 [34]

Answer:

Step-by-step explanation:

You need to set up a ratio for the original recipe and then use that ratio for the new one.

 

If we need 3 cups of flour for every 4 cups of sugar, we have a 3 c flour/4 c sugar ratio, or 3/4

 

The new ratio is 9 c of flour for ? c of sugar. Those ratios have to be the same, so we set up an equation like this:

 

3/4 = 9/?

 

In order to keep the same ratio, you have to multiply by the same number. Since 3*3 = 9, multiply 4*3 to get your answer.

8 0
3 years ago
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