A line passes through the point (0, –1) and has a slope of -2/3. What is the equation of the line?

2 answers:

6 0

Y = mx + b, where m is the slope and b is the y-intercept.

We have the slope of -2/3, so put that instead of m:

y = -2/3x + b

The y-intercept is at (0, -1), so put -1 for b.

y = -2/3 - 1

sesenic [268]3 years ago

5 0

y=-2/3x-1

is the equation

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Can someone please please help me on this algebra problem I’m stuck on answering the question?

Rudik [331]

Explanation:

Midline: it is a horizontal line where half of the function above it and half of the function is below it.

Amplitude: It means how far the function varies from the midline to the above and below.

Period: the distance between two consecutive maximum points (minimum points).

3) From the graph,

$\begin{gathered} \text{Midline}=\frac{Maximum\text{ point+ minimum point}}{2} \\ =\frac{3+(-1)}{2} \\ =\frac{3-1}{2} \\ =\frac{2}{2} \\ =1 \end{gathered}$

Answer: Midline=1

1) Amplitude

$\text{Amplitude =}2$

2) Periods

$\begin{gathered} \text{Period}=6 \\ \Rightarrow b=\frac{2\pi}{6} \end{gathered}$

4) The trigonometric equation is,

$\begin{gathered} y=a\cos (b(x-c))+d \\ a=\text{ amplitude} \\ b=\text{period} \\ c=\text{ phase shift} \\ d=\text{ vertical shift} \\ y=2\cos (\frac{2\pi}{6}x)+1 \end{gathered}$

Answer: