5^3(5^x) the rule is a^b(a^c)=a^(b+c)
5^(3+x)
It would stop at 3y+4>11 because the 3y and 4 are unlike terms and can only be divided or multiplied.
Answer:
7 = -x^2 +16
x^2 -16 = 7
x^2 -23 = 0
Using quadratic equation
x = -0 +- sqrt (23^2 - 4*1*23) / 2 * 1
x = sqrt (0 - -92) / 2
x = sqrt (92) / 2
x1 = 4.7958
x2 = -4.7958
(I tried to answer your question - even though you posted no question - AND you posted no graphics)
Step-by-step explanation:
