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3 years ago

How many grams are in 2.34ml???? 2,340 g 234 g .00234 g .0234 g

Mathematics

1 answer:

Harrizon [31]3 years ago

8 0

Answer:

2.34 grams

Step-by-step explanation:

In this problem, we need to find how many grams in 2.34mL. To solve the problem, we must know the relationship between grams and millilitre.

We know that,

1 milliitre = 1 gram

Hence,

2.34 mL = 2.34 grams.

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Find the area of a triangle with vertices (1, 5), (1, -2), (3,-2).

ollegr [7]

Answer:

Step-by-step explanation:

A(3, - 2), B(1, 5), C(1, - 2)

ΔABC is right angled Δ

AC and BC are legs (cathetus)

$A_{ABC}$ = (AC)(BC) ÷ 2 = $\frac{2*7}{2}$ = 7 units²

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2 years ago

Red copper costs $0.90 for 7.6m and yellow copper costs $1.12 5.2m. Estimate how much each amount of copper costs.

ICE Princess25 [194]

Answer: Red copper = $0.12 per meter

Yellow copper = $0.22 per meter

Step-by-step explanation:

Since Red copper costs $0.90 for 7.6m, the cost of 1m of red copper will be:

= $0.90/7.6

= $0.12

Since yellow copper costs $1.12 5.2m, the cost of 1m of yellow copper will be:

= $1.12 / 5.2

= $0.22 per meter

5 0

2 years ago

A car travels 8 miles in 12 minutes. What is the cars rate in miles per hour

lorasvet [3.4K]

60/12=5. We use the number 60 because60 minutes per hour, 8x5=40. 40mph

6 0

3 years ago

Find the 58"" term of the following arithmetic sequence, 18, 23, 28, 33,

Anna11 [10]

Answer:

303

Step-by-step explanation:

So the equation to find a term is An=a1+(n-1)d

An represents the value of the number (n)

and n is the selective that you want

d is the difference between the first and second term which is 23-18=5, and you can see that adding 5 to the previous term gives the following term.

a1 is the first term in the sequence

so knowing all that now you can go back and inset all variables into the equation

An=18+(58-1)5

An=303

Hope that helps :)

Please give brainliest

6 0

2 years ago

The ratio of money in Terry's bank account to Faye's bank account was 3:5.

inn [45]

Answer:

Terry had £780 initially and Faye had £1300

Step-by-step explanation:

System of Equations

We'll call the following variables:

x = Terry's balance in his bank account

y = Faye's balance in her bank account

The initial relation between them is:

$\frac{x}{y}=\frac{3}{5}$

Cross-multiplying:

5x = 3y [1]

If Terry put £220 in his account he had x+220 and if Faye withdrew £300 from her account, she had y-300. Both quantities are equal, thus

x + 220 = y - 300

Subtracting 220:

x = y - 520 [2]

Substituting in [1]

5(y - 520) = 3y

Multiplying:

5y - 2600 = 3y

Adding 2600 and subtracting 3y:

2y = 2600

Dividing by 2:

y = 1300

From [2]:

x = 1300 - 520

x = 780

Terry had £780 initially and Faye had £1300

7 0

2 years ago