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Leya [2.2K]
3 years ago
13

I need help on my math please

Mathematics
1 answer:
Dovator [93]3 years ago
7 0
In a 2-way frequency table, you take the row entry and divide it by its row total to get a decimal.
For your example:
It starts out like this:
            sunny   snowy
Male:       17      11
Female:   15      16

Add the rows up. 
            sunny   snowy       total
Male:       17      11              28
Female:   15      16             31

Then divide the number the by the total:   
            sunny           snowy       total
Male:       17/28        11/28              28
Female:   15/31        16/31             31      

Yours says to round to the 1000th place, so it ends up like:
            sunny   snowy     
Male:       .607      .393     
Female:    .484      .515
 
 Hope that helps!!    
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Write g(x) = 4x2 + 88x in vertex form. The function written in vertex form is g(x) = (x +11)2 + .
romanna [79]

Answer:

y = 4(x + 11)² - 484

Step-by-step explanation:

y = 4x² + 88x

factor the expression

y = 4(x² + 22x)

complete the square

y + ? = 4(x² + 22x + ?)

y + ? = 4(x² + 22x + 121)

add 4 • 121 to the left side

y + 4 • 121 = 4(x² + 22x + 121)

multiply

y + 484 = 4(x² + 22x + 121)

y + 484 = 4(x + 11)²

subtract both sides by 484

y = 4(x + 11)² - 484

6 0
3 years ago
Read 2 more answers
Try it .............
Veseljchak [2.6K]

Step 1: 3

Step 2: 6

Step 3: 16

Step 4: 8

Step 5: 5

Nice

7 0
3 years ago
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Divide 1/6 by 1/2. Input your answer as a reduced fraction.
ra1l [238]
4/3 or 1 1/3 hope this helps
7 0
3 years ago
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8) BRAINLIEST AND 15 POINTS! PLS HELP ASAP
algol13

Answer:

a.) Between 0.5 and 3 seconds.

Step-by-step explanation:

So I just went ahead and graphed this quadratic on Desmos so you could have an idea of what this looks like. A negative quadratic, and we're trying to find when the graph's y-values are greater than 26.

If you look at the graph, you can easily see that the quadratic crosses y = 26 at x-values 0.5 and 3. And, you can see that the quadratic's graph is actually above y = 26 between these two values, 0.5 and 3.

Because we know that the quadratic's graph models the projectile's motion, we can conclude that the projectile will also be above 26 feet between 0.5 and 3 seconds.

So, the answer is a.) between 0.5 and 3 seconds.

4 0
3 years ago
How many shapes did you put together to make 3/2
ella [17]
You put 3 shapes together I believe
5 0
3 years ago
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