Question

Write a program that uses the function isPalindrome given in Example 6-6 (Palindrome). Test your program on the following strings: madam, abba, 22, 67876, 444244, trymeuemyrt Modify the function isPalindrome of Example 6-6 so that when determining whether a string is a palindrome, cases are ignored, that is, uppercase and lowercase letters are considered the same. The isPalindrome function from Example 6-6 has been included below for your convenience.bool isPalindrome(string str){int length = str.length();for (int i = 0; i < length / 2; i++){if (str[i] != str[length - 1 - i] )return false;}return true;}

Answer 1

Answer:

#include <bits/stdc++.h>

using namespace std;

bool isPalindrome(string str)

{

   char a,b;

int length = str.length();

for (int i = 0; i < length / 2; i++)

{

   a=tolower(str[i]);//Converting both first characters to lowercase..

   b=tolower(str[length-1-i]);

   if (b != a )

return false;

}

return true;

   

}

int main() {

   string t1;

   cin>>t1;

   if(isPalindrome(t1))

   cout<<"The string is Palindrome"<<endl;

   else

   cout<<"The string is not Palindrome"<<endl;

return 0;

}

Output:-

Enter the string

madam

The string is Palindrome

Enter the string

abba

The string is Palindrome

Enter the string

22

The string is Palindrome

Enter the string

67876

The string is Palindrome

Enter the string

444244

The string is not Palindrome

Explanation:

To ignore the cases of uppercase and lower case i have converted every character to lowercase then checking each character.You can convert to uppercase also that will also work.