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3 years ago

14

Fill in the correct formula called a contains numbers from Rhodes 1 to 20 you can use the formula blank to find the volume of th

e largest number divided by the total number of values

Computers and Technology

1 answer:

Flauer [41]3 years ago

5 0

Answer:

Waist

Explanation:

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What is segmentation and paging?

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3 years ago

You can add multiple worksheets to a workbook by clicking the home tab on the ribbon, pressing and holding ____, and then clicki

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3 years ago

Input a list of employee names and salaries and store them in parallel arrays. End the input with a sentinel value. The salaries

4vir4ik [10]

Using the knowledge in computational language in JAVA it is possible to write the code being Input a list of employee names and salaries and store them in parallel arrays

<h3>Writting the code in JAVA:</h3>

<em>BEGIN</em>

<em>DECLARE</em>

<em>employeeNames[100] As String</em>

<em>employeeSalaries[100] as float</em>

<em>name as String</em>

<em>salary, totalSalary as float</em>

<em>averageSalary as float</em>

<em>count as integer</em>

<em>x as integer</em>

<em>rangeMin, rangeMax as float</em>

<em />

<em>INITIALIZE</em>

<em>count = 0;</em>

<em>totalSalary =0</em>

<em />

<em />

<em>DISPLAY “Enter employee name. (Enter * to quit.)”</em>

<em>READ name</em>

<em />

<em>//Read Employee data</em>

<em>WHILE name != “*” AND count < 100</em>

<em />

<em>employeeNames [count] = name</em>

<em>DISPLAY“Enter salary for “ + name + “.”</em>

<em>READ salary</em>

<em>employeeSalaries[count] = salary</em>

<em>totalSalary = totalSalary + salary</em>

<em>count = count + 1</em>

<em />

<em>DISPLAY “Enter employee name. (Enter * to quit.)”</em>

<em>READ name</em>

<em />

<em>END WHILE</em>

<em />

<em>//Calculate average salary with mix , max range</em>

<em>averageSalary = totalSalary / count</em>

<em>rangeMin = averageSalary - 5</em>

<em>rangeMax = averageSalary + 5</em>

<em />

<em>DISPLAY “The following employees have a salary within $5,000 of the mean salary of “ + averageSalary + “.”</em>

<em />

<em>For (x = 0; x < count; x++)</em>

<em>IF (employeeSalaries[x] >= rangeMin OR employeeSalaries[x] <= rangeMax )</em>

<em>DISPLAY employeeNames[x] + “\t” + employeeSalaries[x]</em>

<em>END IF</em>

<em>END FOR</em>

<em>END</em>

See more about JAVA at brainly.com/question/12978370

#SPJ1

5 0

2 years ago

Consider the graph of the function f(x) = 2(x + 3)2 + 2. Over which interval is the graph decreasing? (–∞, –3) (–∞, 2) (–3, ∞) (

Vaselesa [24]

Answer:

The interval over which the graph is decreasing is;

(-∞, -3)

Explanation:

The given function is f(x) = 2·(x + 3)² + 2

By expanding the function, we have;

2·x² + 12·x + 20

From the characteristics of a quadratic equation, we have;

The shape of a quadratic equation = A parabola

The coefficient of x² = +2 (positive), therefore the parabola opens up

The parabola has a minimum point

Points to the left of the minimum point are decreasing

The minimum point is obtained as the x-coordinate value when f'(x) = 0

∴ f'(x) = d(2·x² + 12·x + 20)/dx = 4·x + 12

At the minimum point, f'(x) = 4·x + 12 = 0

∴ x = -12/4 = -3

Therefore;

The graph is decreasing over the interval from -infinity (-∞) to -3 which is (-∞, -3)

Please find attached the graph of the function created with Microsoft Excel

The graph is decreasing over the interval (-∞, -3).

6 0

3 years ago

Read 2 more answers

Will give brainliest and good amount of points, no false answers.

nlexa [21]

The problem with the swap function is that it loses the value at the first index, as soon as it gets overwritten by the value at the second index. This happens in the first statement. To fix it, you need a helper variable.

First you're going to "park" the index at the first index in that helper variable, then you can safely overwrite it with the value at the second index. Then finally you can write the parked value to the second index:

var swap = function(array, firstIndex, secondIndex) {

let helper = array[firstIndex];

array[firstIndex] = array[secondIndex];

array[secondIndex] = helper;

};

I hope this makes sense to you.

7 0

4 years ago