Question

Determine between which consecutive integers the real zeros of f(x) = x^3 - 2 are located.

Answer 1

Answer:

Therefore the zeros of this function are between 1 and 2. So the correct answer is "a".

Step-by-step explanation:

In order to find the zeros of a function we need to find at which values for "x" make f(x) equal to zero. Therefore we have:

$f(x) = x^3 - 2 \\0 = x^3 - 2\\x^3 - 2 = 0\\x^3 = 2\\x = \sqrt[3]{2} = 1.2599$

Therefore the zeros of this function are between 1 and 2. So the correct answer is "a".