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Solve system of equations using any method 2x-6y=8 and 2x-6y=3
2 answers:
Let z be any number (like x would be) if we set z equal to 2x-6y, then we get z = 2x-6y The system 2x-6y = 8 2x-6 = 3 turns into this new system z = 8 z = 3 but z is a single number. It can't be both 8 and 3 at the same time. So there are no solutions
The answer is no solution. If you use elimination, by subtracting the second equation from the first, you come out with 0=5, which is a false statement. Therefore, there is no solution.
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