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devlian [24]
3 years ago
5

Help please =] Solve system of equations using any method 2x-6y=8 and 2x-6y=3

Mathematics
2 answers:
dusya [7]3 years ago
6 0
Let z be any number (like x would be)

if we set z equal to 2x-6y, then we get z = 2x-6y

The system 

2x-6y = 8
2x-6 = 3

turns into this new system

z = 8
z = 3

but z is a single number. It can't be both 8 and 3 at the same time. So there are no solutions
romanna [79]3 years ago
3 0
The answer is no solution. If you use elimination, by subtracting the second equation from the first, you come out with 0=5, which is a false statement. Therefore, there is no solution.
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PLEASE CHECK MY ANSWERS (PART 2)
Anna007 [38]
3 is incorrect, should be 28.9

16^2 + 18^2 = EG^2
256 + 324
580 = EG^2
EG ≈ 24.08

16^2 + 24.08^2 = AG^2
256 + 580 = AG^2
836 = AG^2
AG ≈ 28.9

5 is incorrect:

The base is 8.
Draw an altitude the base.
Since the triangle is isoceles, it divides the base in half.
Half of that base is 4.
Two right triangles have been formed with one leg 4 and hypotenuse 8.
4^2 + b^2 = 8^2
16 + b^2 = 64
b^2 = 48
b ≈ 6.93

The height of the triangle is 6.93, the base is 8.
A = bh/2 = 8*6.93/2 ≈ 27.7 ≈ 28



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Step-by-step explanation:

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\circ \: \: { \underline{ \boxed{ \sf{ \color{green}{Happy\:learning.}}}}}∘

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