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ycow [4]
3 years ago
14

1. The number a is 4/5 of the number b. What part of number a is number b?

Mathematics
1 answer:
alexdok [17]3 years ago
7 0
Writing some equations out might help!

1) You know that a is 4/5 of b. This can be written as:a =  \frac{4}{5} b.
To find what b is equal to, multiply both sides by 5/4: \frac{5}{4}a = b.
A is 5/4 B. 

2) You know that a is 1/5 smaller than b. This can be written as: a = b - \frac{1}{5}.
To find b, just add 1/5 to both sides: a +  \frac{1}{5} = b.
B is 1/5 bigger than a. 
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Alan wants to install security cameras in his store, which has dimensions of 30 feet by 30 feet. Each camera can view an area of
FinnZ [79.3K]
30×30=900
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8 0
3 years ago
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−4p+9=−5<br><br><br> Plzzzzzzz help
Hoochie [10]

Answer:

p = 3.5 or p = 7/2

Step-by-step explanation:

-4p+9= -5

or, -4p = - 14

or, p = -14/-4

or, p = 7/2 = 3.5

5 0
3 years ago
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Use numerals instead of words. If necessary, use / for the fraction bar(s). A parabola is given by the equation y = x2 + 4x + 4.
Anarel [89]
<span><span>Graph <span>x2<span> = 4</span>y</span><span> and state the vertex, focus, axis of symmetry, and directrix.</span></span><span>This is the same graphing that I've done in the past: </span><span>y = (1/4)x2</span><span>. So I'll do the graph as usual:</span></span><span> </span><span>The vertex is obviously at the origin, but I need to "show" this "algebraically" by rearranging the given equation into the conics form:<span>x2 = 4y</span> Copyright © Elizabeth Stapel 2010-2011 All Rights Reserved<span>
(x – 0)2 = 4(y – 0)</span><span>This rearrangement "shows" that the vertex is at </span><span>(h, k) = (0, 0)</span><span>. The axis of symmetry is the vertical line right through the vertex: </span><span>x = 0</span>. (I can always check my graph, if I'm not sure about this.) The focus is "p" units from the vertex. Since the focus is "inside" the parabola and since this is a "right side up" graph, the focus has to be above the vertex.<span>From the conics form of the equation, shown above, I look at what's multiplied on the unsquaredpart and see that </span><span>4p = 4</span><span>, so </span><span>p = 1</span><span>. Then the focus is one unit above the vertex, at </span>(0, 1)<span>, and the directrix is the horizontal line </span><span>y = –1</span>, one unit below the vertex.<span>vertex: </span>(0, 0)<span>; focus: </span>(0, 1)<span>; axis of symmetry: </span><span>x<span> = 0</span></span><span>; directrix: </span><span>y<span> = –1</span></span></span><span><span><span>Graph </span><span>y2<span> + 10</span>y<span> + </span>x<span> + 25 = 0</span></span>, and state the vertex, focus, axis of symmetry, and directrix.</span><span>Since the </span>y<span> is squared in this equation, rather than the </span>x<span>, then this is a "sideways" parabola. To graph, I'll do my T-chart backwards, picking </span>y<span>-values first and then finding the corresponding </span>x<span>-values for </span><span>x = –y2 – 10y – 25</span>:<span>To convert the equation into conics form and find the exact vertex, etc, I'll need to convert the equation to perfect-square form. In this case, the squared side is already a perfect square, so:</span><span>y2 + 10y + 25 = –x</span> <span>
(y + 5)2 = –1(x – 0)</span><span>This tells me that </span><span>4p = –1</span><span>, so </span><span>p = –1/4</span><span>. Since the parabola opens to the left, then the focus is </span>1/4<span> units to the left of the vertex. I can see from the equation above that the vertex is at </span><span>(h, k) = (0, –5)</span><span>, so then the focus must be at </span>(–1/4, –5)<span>. The parabola is sideways, so the axis of symmetry is, too. The directrix, being perpendicular to the axis of symmetry, is then vertical, and is </span>1/4<span> units to the right of the vertex. Putting this all together, I get:</span><span>vertex: </span>(0, –5)<span>; focus: </span>(–1/4, –5)<span>; axis of symmetry: </span><span>y<span> = –5</span></span><span>; directrix: </span><span>x<span> = 1/4</span></span></span><span><span>Find the vertex and focus of </span><span>y2<span> + 6</span>y<span> + 12</span>x<span> – 15 = 0</span></span></span><span><span>The </span>y<span> part is squared, so this is a sideways parabola. I'll get the </span>y stuff by itself on one side of the equation, and then complete the square to convert this to conics form.<span>y2 + 6y – 15 = –12x</span> <span><span>
y</span>2 + 6y + 9 – 15 = –12x + 9</span> <span>
(y + 3)2 – 15 = –12x + 9</span> <span>
(y + 3)2 = –12x + 9 + 15 = –12x + 24</span> <span>
(y + 3)2 = –12(x – 2)</span> <span>
(y – (–3))2 = 4(–3)(x – 2)</span></span><span><span>Then the vertex is at </span><span>(h, k) = (2, –3)</span><span> and the value of </span>p<span> is </span>–3<span>. Since </span>y<span> is squared and </span>p<span> is negative, then this is a sideways parabola that opens to the left. This puts the focus </span>3 units to the left of the vertex.<span>vertex: </span>(2, –3)<span>; focus: </span><span>(–1, –3)</span></span>
6 0
3 years ago
Triangle ABC is dilated to form new triangle DEF. If angle A is congruent to angle D, what other information will prove that the
goldfiish [28.3K]

Answer:

angle c is congruent to angle D.

Step-by-step explanation:

7 0
2 years ago
Read 2 more answers
Drag each expression to show whether it can be used to find the volume, surface area, or neither.
Mumz [18]

Answer:

Volume = 12 *6 *8 , Surface area = 2 ( 12 *6  + 8 *12 + 6* 8 )

Step-by-step explanation:

Given : Cuboid with length 12 , width 6 and height 8 units.

To find : Drag each expression to show whether it can be used to find the volume, surface area, or neither.

Solution : We have given Cuboid with

Length =  12 units ,

Width = 6 units

Height = 8 units.

Volume of cuboid = length * width * height .

Volume = 12 *6 *8.

Surface area = 2 ( l *w  + h *+w *h)

Surface area = 2 ( 12 *6  + 8 *12 + 6* 8 ).

None = 12 +6 +8.

Therefore, Volume = 12 *6 *8 , Surface area = 2 ( 12 *6  + 8 *12 + 6* 8 ) .

7 0
3 years ago
Read 2 more answers
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