Answer:
if(y==10)
{
x=0; // assigning 0 to x if y equals 10.
}
else
{
x=1; // assigning 1 to x otherwise.
}
Explanation:
In the if statement i have used equal operator == which returns true if value to it's right is equal to value to it's left otherwise false.By using this operator checking value of y and if it is 10 assigning 0 to x and if it is false assigning 1 to x.
Answer:
This is correct. And to remove the confusion, I am adding the meaning of the Pseudocode. You need to begin with the algo that you are working upon, and then you need it to phrase the algo with the words which are easy to be transcribed in the form of the computer instructions. Now you need to indent the instructions properly inside the loop or within the conditional clauses. And while doing this, you need to not use the words which are used in certain forms of computer language. However, IF and THEN and ELSE and ENDIF are very frequently used as pseudo-code. Hence, your answer is correct.
Explanation:
Please check the answer section.
Answer:
Here’s one!
Given [math]R[/math], the radius of the circle.
Let [math]N,D\leftarrow 0[/math]
Repeat until [math]D[/math] is large enough (about 1,000,000)
[math]x,y\leftarrow U[0,1][/math]
If [math]x^2 + y^2\le 1[/math] then [math]N\leftarrow N+1[/math]
[math]D\leftarrow D+1[/math]
[math]P\leftarrow\frac{8NR}{D}[/math]
Return [math]P[/math]
[math]U[0,1][/math] is a uniform random number in the range [math][0,1][/math].
Explanation:
Answer:
Answer is Mobile commerce
