How do you get The gold chip on Megaman x3 snes I want To know

Which statement is false? Classes are reusable software components. A class is to an object as a blueprint is to a house. Perfor

Korolek [52]

Answer:

The last option i.e "A class is an instance of its object" is the correct answer of this question.

Explanation:

A class is a collection of variable and method . The class is the blueprint of the object that means class is physical space entity and object is a runtime space entity.It is the the reusability feature of the programming component.

Following are the syntax to declare any class.

Class classname

<u>For Example</u>: class test1

With the help of class we can achieve the inheritance, encapsulation and abstraction etc.

All the other options except the last one are correct option. Because option(1), option(2) and option(3) follow the property of class and object . that's why last option is False.

4 0

3 years ago

Which of the following hacker attacks against wireless networks are virtually undetectable?

Ede4ka [16]

Answer: A. passive attacks

Explanation:

Passive attack is a type of attack where by a system is tracked and scanned to determine how vulnerable it is and to also detect open port. The major purpose of a passive attack on a network is to gain access to the information of the target without altering the data.

A passive attack on a network may not be necessarily malicious, it is a type of network attack that is very difficult to detect.

Methods of carrying out passive attacks.

•War driving: scanning of networks is carried out to detect Wi-Fi that are vulnerable.

•Dumpster driving: Attackers or intruders search for information from discarded computers and

other gadgets, those information can help to attack a network.

7 0

4 years ago

When you were configuring Encrypting File System (EFS) in the lab, a __________ on the Documents folder in the File Explorer ind

harina [27]

I’m not 100% sure but I think it’s a padlock that represents it

3 0

4 years ago

Which line in the following program will cause a compiler error? #include using namespace std; int main() { int number =5; if (n

DanielleElmas [232]

Answer:

#include <iostream>
using namespace std;
int main() {
int number =5;
if (number>=0&& number <=100){
cout<<"passed.\n";
}
else{
cout<<"failed.\n";
}
return 0;
}

Explanation:

There where multiple errors in the code given in the questions

Line 1: Missing <iostream>

Line 5: The comparison operator was wrong correction is highlighted

Line 12 Missing closing brace for the main function

All the errors have been fixed and the code above compiles

4 0

3 years ago

In this exercise you will debug the code which has been provided in the starter file. The code is intended to do the following:

abruzzese [7]

Answer:

The corrected code is as follows:

import java.util.Scanner;

public class U2_L4_Activity_Two{

public static void main(String[] args){

Scanner scan = new Scanner(System.in);

String str1 = scan.nextLine();

String str2 = str1;

str1 = str1.toUpperCase();

System.out.println(str1);

System.out.println(str2);

}

Explanation:

This corrects the scanner object

Scanner scan = new Scanner(System.in);

This line is correct

String str1 = scan.nextLine();

This copies str1 to str2

String str2 = str1;

This converts str1 to upper case

str1 = str1.toUpperCase();

This prints str1

System.out.println(str1);

This prints str2

System.out.println(str2);

8 0

3 years ago