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atroni [7]
4 years ago
5

What is the total perimeter of this figure?

Mathematics
1 answer:
wel4 years ago
3 0
I would say ummmmmmm probably 31.71
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Write a 5 colum proof proving the following.
SVETLANKA909090 [29]

Answer:

cjjjjj

Step-by-step explanation:

abcdsk,kghmlihmgcss

6 0
3 years ago
(x2 + 10x + 21) - (x + 7)
rusak2 [61]

Answer:

11x+14

Step-by-step explanation:

(2x+10x+21)-x-7 = 12x+21-x-7 = 11x+14

3 0
3 years ago
Round $650 to the nearest hundred and multiply that amount by 7%.
Lunna [17]
The answer will be 49
because 650 will be rounded up to 700 then multiply that by 7% which gives you 49
6 0
3 years ago
Read 2 more answers
Lieutenant Commander Data is planning to make his monthly (every 30 days) trek to Gamma Hydra City to pick up a supply of isolin
Nookie1986 [14]

Answer:

a

 N  =  209 \ unites

b

 N_{max}  =  249  

Step-by-step explanation:

From the question we are told that

   The daily demand is  d =  7/day

   The  standard deviation is  \sigma  =  3 /day

   The  service probability is  s =  95\%  =  0.95

    The number of chips  in the inventory is k  =  40

   The number of days in his monthly is  T =  30 \  days

    The lead time is  L  =  4

 

Generally the number he should order (optimal order ) is mathematically represented as

      N  =  d(L  +  T)+(\sigma_{T + L}  * z)  -k

Here \sigma__{T+L }} is the monthly standard deviation which is mathematically evaluated as

            \sigma__{T  + L}} =  \sqrt{(T + L) * 1^2}

=>         \sigma__{T  + L}}  =  \sqrt{34}

=>          \sigma__{T+L}} =  5.83

Also  z-value  for the  95% service probability  from the z-table  is  1.96

So

      N  =  7 *  (30 +4 ) + (1.96 *  5.83) - 40

=>     N  =  209 \ unites

For the maximum order quantity  k =  0

So

    N_{max} = d(L  +  T)+(\sigma_{T + L}  * z)  -0

=> N_{max}  =  7 *  (30 +4 ) + (1.96 *  5.83) - 0

=>  N_{max}  =  249  

7 0
3 years ago
When steve woke up. his temperature was 102o
Inessa05 [86]
Um.. Not exactly sure how too work with temperature, but with basic math
99oF im assuming 
Worth a shot
5 0
3 years ago
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