Answer:
m<FAB = 75°
m<BAC = 105°
Step-by-step explanation:
First, find the value of x.
(13x - 3)° = (3x + 2)° + 55° (exterior angle theorem of a ∆)
Solve for x
13x - 3 = 3x + 2 + 55
13x - 3 = 3x + 57
Collect like terms
13x - 3x = 57 + 3
10x = 60
Divide both sides by 10
x = 6
✔️m<FAB = 13x - 3
Plug in the value of x
m<FAB = 13(6) - 3 = 78 - 3
m<FAB = 75°
✔️m<BAC = 180 - m<FAB (angles on a straight line/supplementary angles)
m<BAC = 180 - 75 (substitution)
m<BAC = 105°
For this case we have that the original point is given by:
B = (7, 2)
As the point is reflected through the x axis, then we have the following transformation:
(x, y) --------------> (x, -y) -------------> (x ', y')
Applying the transformation to the original ordered pair we have:
(7, 2) --------------> (7, - (2)) -------------> (7, -2)
Answer:
Point B 'is given by:
B '= (7, -2)
Answer:
x=-2
Step-by-step explanation:
Since it is an equilateral triangle (note the little lines across the legs of corner 2) the other angle must be 69° as well.
That leaves 180-69-69 = 42 for ∠2.
So x + 44 = 42 => x = 42-44 = -2.
