The second one orate 3rd one
Group points {(0,1),(0,5)(2,6),(3,3)}is not a function, but group points {(1,4)(2,7)(3,1)(5,7)} is a function. What do you notic
Tasya [4]
<h2>Any value in the domain of the function should have a unique value in codomain.</h2>
Step-by-step explanation:
In the first set of points 

,
value
maps to two distinct values
in the codomain.
This violates the property of functions.
The first set of points does not form a function.
In the second set of points 

,
Every value in domain corresponds to unique value in domain.
There is no violation in the property of functions.
The second set of points does form a function.
180 is the answer....
angle B =50
angle C = 130
The set of all possibilities is called sample space and is denoted by S.
So, S = {NBD, NDB, BDN, BND, DBN, DNB} and n(S) = 8
and we need to find the probability of NBD
E = {NBD} and n(E) = 1
The probability of an even is defined by p(E) = 
Hence, p(E) = 
Answer:
w=17
Step-by-step explanation:
-243=-9(10+w)
-243=-90-9w
+90 +90
-153=-9w
17=w
hope this helps :)