All categories

3 years ago

A triangle-shaped machine part has sides of 2 1/2 inches, 3 1/4 inches, and 5 inches. The triangle's perimeter is

Mathematics

1 answer:

SOVA2 [1]3 years ago

8 0

Answer:

Step-by-step explanation:

The perimeter of any shape is the distance around the edge of the shape. It is found by adding the side lengths of each side together.

Add each side length listed for the triangle part.

$P = 2\frac{1}{2} + 3\frac{1}{4} + 5 \\P = 2\frac{2}{4} + 3\frac{1}{4} + 5\\P = 10 \frac{3}{4}$

You might be interested in

An arc on a circle measures 85°. The measure of the central angle, in radians, is within which range?

BigorU [14]

0 to π/2 radians i might be wrong but i tried helping

3 0

3 years ago

Read 2 more answers

Ok your very lucky if you see this..what’s 2+2 but you have to give reasoning

ANEK [815]

Answer:

4

Step-by-step explanation:

2 + 2 = 4

1 + 1 = 2 + 1 = 3 + 1 = 4

Don't know why I did this but ok.

4 0

3 years ago

Read 2 more answers

√6.76 +5.4= evaluate

Sav [38]

The answer is 8 hope this helps

4 0

3 years ago

Which equation has the solutions X=1 +-SQRT 5?

Vesna [10]

Answer:

D is correct. $x^2-2x-4=0$

Step-by-step explanation:

We are given the root of the equation

$x=1+\pm \sqrt{5}$

If we are given solution of the equation then find equation using formula.

If a and b are the solution of equation then equation would be (x-a)(x-b)=0

Here, $a=1+\sqrt{5} , b=1-\sqrt{5}$

Equation form would be $(x-1-\sqrt{5})(x-1+\sqrt{5})=0$

Now we simplify the above equation to get correct option.

$x^2-x+x\sqrt{5}-x+1-\sqrt{5}-x\sqrt{5}+\sqrt{5}-5=0$

$x^2-2x-4=0$

So, D is correct. $x^2-2x-4=0$

8 0

4 years ago

Read 2 more answers

HURRY IM ON A TIME LIMIT WILL MARK YOU BRAINLIEST

Galina-37 [17]

Answer:

x=2.75

Step-by-step explanation:

4x+5=8x-6

4x-8x=-6-5

-4x=-11

divide -4 by both sides

x=2.75

7 0

3 years ago