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2 years ago

Why do you think y= ax+b is called a linear equation Please help

Mathematics

2 answers:

Mila [183]2 years ago

4 0

Step-by-step explanation:

Hey there!

Reason:

The power of the term is one.
It can be graphed in a at. line on graph.

You can simply define linear equation as the equation which has two variables with 1 exponent.

So, you can graph out that why it is called linear equation. It have two variables with 1 exponent.

Hope it helps..

Shalnov [3]2 years ago

3 0

Answer:

Y=mx+b Is a linear equasion because if you plot the x and y on a graph it always shows a straight line.

Step-by-step explanation:

For example, y=7x+9,

When x is 1 y is 16, and

when x is 2 y is 23.

When you put those two points on a graph and connect the dots with a ruler, you get a straight line, and you will automatically find that when x is 3 y is 30.

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Find the volume in cubic meter (C.U.M) of each of the cuboid whose dimensions are :

Leno4ka [110]

The volume in cubic meter of the cuboid with the dimensions length = 12 m , breadth = 10m, height = 4.5 m is 540 m³

<h3 />

<h3>Volume of a cuboid:</h3>

v = lwh

where

l =- length

w = width

h = height

Therefore,

l = 12 m

w = 10 m

h = 4.5

v = 12 × 10 × 4.5

v = 120 × 4.5

v = 540 m³

learn more on cuboid here: brainly.com/question/14297267?referrer=searchResults

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3 years ago

Write the absolute value equation given the transformations

Evgesh-ka [11]

Answer:

y = - 0.5 | x - 5 | + 2 

Step-by-step explanation:

g(x) = |x|

$1^{st}$ step - shifts right 5 units: g(x + 5) = | x - 5 |

$2^{nd}$ step - shifts up 2 units: g(x + 5) + 2 = | x - 5 | + 2

$3^{rd}$ step - reflected: - g(x + 5) + 2 = - | x - 5 | + 2

$4^{th}$ step - stretched by 0.5: y = - 0.5 | x - 5 | + 2

y = - 0.5 | x - 5 | + 2

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3 years ago

Let T be the plane-2x-2y+z =-13. Find the shortest distance d from the point Po=(-5,-5,-3) to T, and the point Q in T that is cl

GaryK [48]

Answer:

d=10u

Q(5/3,5/3,-19/3)

Step-by-step explanation:

The shortest distance between the plane and Po is also the distance between Po and Q. To find that distance and the point Q you need the perpendicular line x to the plane that intersects Po, this line will have the direction of the normal of the plane $n=(-2,-2,1)$ , then r will have the next parametric equations:

$x=-5-2\lambda\\y=-5-2\lambda\\z=-3+\lambda$

To find Q, the intersection between r and the plane T, substitute the parametric equations of r in T

$-2x-2y+z =-13\\-2(-5-2\lambda)-2(-5-2\lambda)+(-3+\lambda) =-13\\10+4\lambda+10+4\lambda-3+\lambda=-13\\9\lambda+17=-13\\9\lambda=-13-17\\\lambda=-30/9=-10/3$

Substitute the value of $\lambda$ in the parametric equations:

$x=-5-2(-10/3)=-5+20/3=5/3\\y=-5-2(-10/3)=5/3\\z=-3+(-10/3)=-19/3\\$

Those values are the coordinates of Q

Q(5/3,5/3,-19/3)

The distance from Po to the plane

$d=\left| {\to} \atop {PoQ}} \right|=\sqrt{(\frac{5}{3}-(-5))^2+(\frac{5}{3}-(-5))^2+(\frac{-19}{3}-(-3))^2} \\d=\sqrt{(\frac{5}{3}+5))^2+(\frac{5}{3}+5)^2+(\frac{-19}{3}+3)^2} \\d=\sqrt{(\frac{20}{3})^2+(\frac{20}{3})^2+(\frac{-10}{3})^2}\\d=\sqrt{\frac{400}{9}+\frac{400}{9}+\frac{100}{9}}\\d=\sqrt{\frac{900}{9}}=\sqrt{100}\\d=10u$

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3 years ago

Please help! Write the slope-intercept form equation of the trend line

Eduardwww [97]

Answer:

y= -1/3x+9.2

Step-by-step explanation:

I believe that it is 9.2 although it could be another number in the 9's.

The slope is (rise) -1 and (run) 3 and the line crosses the y-intercept at what it looks like 9.2

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3 years ago