No, 21 is a multiple of 7
Remember these two combinations: logab=loga+logb, log(a/b)=loga-logb
3logx=logx^3
(1/2)log(x+2)=log(x+2)^(1/2)
2log(z-4)=log(z-4)^2
so the given expression can be combined into log{[(x^3)(z-4)^2]/(x+2)^(1/2)}
Answer:
3
Step-by-step explanation:
3 would be the degree of the polynomial since it has the highest degree.
4:5
explanation-
Express the given ratios as fraction
4 : 5 = 4/5 and 2 : 3 =2/3
Now find the L.C.M (least common multiple) of 5 and 3
The L.C.M (least common multiple) of 5 and 3 is 15.
Making the denominator of each fraction equal to 15, we have
4/5 = (4 ×3)/(5 ×3) = 12/15 and 2/3 = (2 ×5)/(3 ×5) = 10/15
Clearly, 12 > 10
Now, 12/15 > 10/15
Therefore, 4 : 5 > 2 : 3.
