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Anna007 [38]
3 years ago
6

A video game sets the points needed to reach the next level based on the function g(x) = 7(3)^x − 1, where x is the current leve

l. The hardest setting promises to multiply the points needed in each level according to the function h(x) = 4x. How many points will a player need on the hardest setting of level 4?
Mathematics
1 answer:
inna [77]3 years ago
5 0
Well, using the current level function of g(x), the player on level 4 will then need 7(3)⁴-1 to get to the next level.

however, if the player is using the hardest setting, the hardest setting promises to quadruple any points on the current level, so, he/she will only need a quarter of 7(3)⁴-1.

now, 7(3)⁴-1 is 566, however, you don't need all 566 in hardest setting, you can do with only 566/4, since the hardest setting will give you 4x or quadruple of the amount of points.
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A credit card company decides to study the frequency with which its cardholders charge for items from a certain change of retail
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Answer:

15.87% of the total number of cardholder would be expected to be charging 27 or more in the study.

Step-by-step explanation:

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Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Mean of 25 charged purchases and a standard distribution of 2

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1 subtracted by the pvalue of Z when X = 27. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{27 - 25}{2}

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Out of the total number of cardholders about how many would you expect are charging 27 or more in the study?

0.1587*100% = 15.87%

15.87% of the total number of cardholder would be expected to be charging 27 or more in the study.

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