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2 years ago

Juan Carlos graphs the functions f(x) = 8x - 2 and g(x) = -8x + 2

Mathematics

1 answer:

Mamont248 [21]2 years ago

8 0

Answer:

$x = 0.25$

Step-by-step explanation:

Given

$f(x) = 8x - 2\\ g(x) = -8x + 2$

Required

Determine their point of intersection

To do this, we simply do:

$f(x) = g(x)$

This gives:

$8x - 2 = -8x + 2$

Collect Like Terms

$8x + 8x = 2 + 2$

$16x = 4$

Solve for x

$x = 4/16$

$x = 0.25$

Hence:

Their point of intersection is at $x = 0.25$

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(25 points) Ricardo wants to mix 1 part yellow paint to 3 parts blue paint to make a certain shade

Lapatulllka [165]

Answer:

6 pints of blue

Step-by-step explanation:

note- 8 pints = 1 gallon

Original ratio- 3 parts blue to 1 part yellow ( 3b:1y)

This will make 4 pints if we say that 1 part can be one pint
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Divide the amount needed by how much one portion will make

8/4= 2

Multiply original ratio by 2 to see how many pints of each he’ll need for his new amounts

1y*2= 2 pints yellow paint

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Let me know if you have any questions and I hope this helps! :)

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1 year ago

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Answer:

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Step-by-step explanation:

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2 years ago

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finlep [7]

+8 is the greatest then -8

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3 years ago

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A bicycle store costs $2700 per month to operate. The store pays an average of $65 per bike. The average selling price of each

vladimir2022 [97]

Answer:$90

Step-by-step explanation:

how much they sell for $95 minus how much they cost $65 equals $30 then divid how much rent is $2700 by the $30 equals $90

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3 years ago

What is the expression in radical form?<br><br> (4x3y2)310

sertanlavr [38]

Given:

Consider the given expression is

$(4x^3y^2)^{\frac{3}{10}}$

To find:

The radical form of given expression.

Solution:

We have,

$(4x^3y^2)^{\frac{3}{10}}=(2^2)^{\frac{3}{10}}(x^3)^{\frac{3}{10}}(y^2)^{\frac{3}{10}}$

$(4x^3y^2)^{\frac{3}{10}}=(2)^{\frac{6}{10}}(x)^{\frac{9}{10}}(y)^{\frac{6}{10}}$

$(4x^3y^2)^{\frac{3}{10}}=(2)^{\frac{3}{5}}(x)^{\frac{9}{10}}(y)^{\frac{3}{5}}$

$(4x^3y^2)^{\frac{3}{10}}=\sqrt[5]{2^3}\sqrt[10]{x^9}\sqrt[5]{y^3}$ $[\because x^{\frac{1}{n}}=\sqrt[n]{x}]$

$(4x^3y^2)^{\frac{3}{10}}=\sqrt[5]{8y^3}\sqrt[10]{x^9}$ $[\because x^{\frac{1}{n}}=\sqrt[n]{x}]$

Therefore, the required radical form is $\sqrt[5]{8y^3}\sqrt[10]{x^9}$ .

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3 years ago