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Alex73 [517]
3 years ago
6

The answer I got was x is less than or equal to 2 but I’m not sure if I’m correct

Mathematics
2 answers:
Alecsey [184]3 years ago
4 0
You're correct.  I like how you told us what your answer was first and then just asked for reassurance in your ideas.  I think that's how you should use brainly.
Lapatulllka [165]3 years ago
3 0
Yeah ur correct my frnd
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Find the​ (a) mean,​ (b) median,​ (c) mode, and​ (d) midrange for the given sample data. An experiment was conducted to determin
egoroff_w [7]

Answer:

The mean phenotype code is 2.72

The median phenotype code is 2.52

The mode phenotype code is 2.

The midrange of the phenotype codes is 2.52

B Only the mode makes sense since the data is nominal.

Step-by-step explanation:

5 0
3 years ago
A recipe uses 1/4 teaspoon of salt and 2 1/2 teaspoons of sugar. What is the ratio of salt to sugar in this recipe?​
KATRIN_1 [288]

Answer:

1:10

Step-by-step explanation:

the ratio we can it is

\frac{amount\:salt}{amount\:sugar}\\\\\frac{\frac{1}{4}}{2\frac{1}{2}}\\\\\frac{\frac{1}{4}}{\frac{5}{2}}\\\\\frac{1\times2}{4\times5}\\\\\frac{1}{2\times5}\\\\\frac{1}{10}

so the ratio is 1:10

5 0
2 years ago
A two way table shows information about pupils in a primary school
arlik [135]

Answer:

42 boys can count (given)

P(boy & can count) = 0.35

Step-by-step explanation:

P(boy who can count) = 42/120

7/20 = 0.35

7 0
3 years ago
A union of restaurant and foodservice workers would like to estimate the mean hourly wage, μ, of foodservice workers in the U.S.
pav-90 [236]

Answer:

n=(\frac{1.960(2.25)}{0.35})^2 =158.76 \approx 159

So the answer for this case would be n=159 rounded up to the nearest integer

Step-by-step explanation:

Assuming this complete question: A union of restaurant and foodservice workers would like to estimate the mean hourly wage, , of foodservice workers in the U.S. The union will choose a random sample of wages and then estimate using the mean of the sample. What is the minimum sample size needed in order for the union to be 95% confident that its estimate is within $0.35 of ? Suppose that the standard deviation of wages of foodservice workers in the U.S. is about $2.15 .

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

\bar X represent the sample mean for the sample  

\mu population mean (variable of interest)

\sigma=2.25 represent the population standard deviation

n represent the sample size  

Solution to the problem

Since the Confidence is 0.95 or 95%, the value of \alpha=0.05 The margin of error is given by this formula:

ME=z_{\alpha/2}\frac{s}{\sqrt{n}}    (a)

And on this case we have that ME =0.35 and we are interested in order to find the value of n, if we solve n from equation (a) we got:

n=(\frac{z_{\alpha/2} \sigma}{ME})^2   (b)

The critical value for 95% of confidence interval now can be founded using the normal distribution. And in excel we can use this formla to find it:"=-NORM.INV(0.025;0;1)", and we got z_{\alpha/2}=1.960, replacing into formula (b) we got:

n=(\frac{1.960(2.25)}{0.35})^2 =158.76 \approx 159

So the answer for this case would be n=159 rounded up to the nearest integer

3 0
2 years ago
16 ÷ ( 2/5 + 2/ 3 ).
77julia77 [94]

Answer:

15

Step-by-step explanation:

16 % (2/5 + 2/3) = 16 % (6/15 + 10/15) = 16 % 16/15 = 16/1 x 15/16 = 240 % 16 = 15

4 0
3 years ago
Read 2 more answers
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