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Alex73 [517]
4 years ago
6

The answer I got was x is less than or equal to 2 but I’m not sure if I’m correct

Mathematics
2 answers:
Alecsey [184]4 years ago
4 0
You're correct.  I like how you told us what your answer was first and then just asked for reassurance in your ideas.  I think that's how you should use brainly.
Lapatulllka [165]4 years ago
3 0
Yeah ur correct my frnd
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suppose the population of a certian city is 3784 thousand it is expected to decrease to 3001 thousand in 50 years find the perce
scoundrel [369]

Answer:

96%

Step-by-step explanation:

96% decrease

7 0
3 years ago
If log.. (125) = 3, then x =
Naddik [55]
5x5x5=125 so it could be x=5
6 0
3 years ago
All currently has $25. He is going to start saving $5 every week
sergij07 [2.7K]

Answer:

I believe the answer is b  

Step-by-step explanation: I think the answer is b because he gets $5 every week and he already has $25 the only thing we dont know is the weeks and you multiply 5 by the weeks so, 5(how much he gets each week) times x (The amount of weeks) plus 25(the amount he already has) equals y(the amount of everything put together)

5 0
3 years ago
I need help with this
defon

i guess just times them all then divide up by how many numbers you have

3 0
4 years ago
A spotlight on the ground shines on a wall 12 m away. If a man 2 m tall walks along the x-axis from the spotlight toward the bui
Sedbober [7]

Answer:

0.675 m/s

Step-by-step explanation:

Let height of shadow= y,CD=x

Height of man=2 m

Speed of man= \frac{dx}{dt}=1. 8 m/s

\triangle ABD\sim\triangle ECD

Therefore, \frac{AB}{EC}=\frac{BD}{CD}

\frac{y}{2}=\frac{12}{x}

xy=24

Differentiate w.r.t t

x\frac{dy}{dt}+y\frac{dx}{dt}=0

x\frac{dy}{dt}=-y\frac{dx}{dt}

\frac{dy}{dt}=-\frac{y}{x}\frac{dx}{dt}

When the man is 4 m from  the building

Then, we have x=12-4=8 m

\frac{dx}{dt}=1.8 m/s

Substitute the values in above equation then, we get

8y=24

y=\frac{24}{8}=3

Substitute the values then we get

\frac{dy}{dt}=-\frac{3}{8}\times 1.8=-0.675 m/s

Hence, the length of his shadow on the building decreasing at the rate 0.675 m/s.

8 0
3 years ago
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