<em>Look</em><em> </em><em>at</em><em> </em><em>the</em><em> </em><em>attached</em><em> </em><em>picture</em>
<em>Hope </em><em>it</em><em> </em><em>will</em><em> </em><em>help</em><em> </em><em>you</em>
<em>Good</em><em> </em><em>luck</em><em> </em><em>on</em><em> </em><em>your</em><em> </em><em>assignment</em>
Answer:
V≈536.38
Step-by-step explanation:
V=a3
Answer:
<h2><u><em>
8x -2</em></u></h2>
Step-by-step explanation:
Subtract:
-6x-3 from 2x-5
2x - 5 -(-6x - 3) =
2x - 5 + 6x + 3 =
8x -2
Question is a bit vague. If you wish to graph this inequality, you'll need to know what the graph of the absolute value function y = |x| looks like; it's a " V " with the vertex at the origin. The slope of the right half of the graph is m=1. Draw this function.
Next, subtract 2 from both sides. We'll get <span> |x + 1| < –1 - 2
or
</span> |x + 1| < –3. We can stop here! Why! because the absolute value function is never smaller than zero, and so <span> |x + 1| is never smaller than -3.
You could, of course, graph y = |x+1|; start with your graph for y = |x| and then move the whole graph 1 unit to the left (away from the origin). If you do this properly you'll see that the entire graph is above the x-axis, except for the vertex (-1,0). Again, that tells us that the given inequality has no solution.
</span>
C = 2πr
divide by 2π
C/2π = r
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