Question

Solve the following system of equations please ASAP

Answer 1

Given:

The system of equation:

$x+y = -4$ -------- (1)

$y = x^{2} -6x$ --------- (2)

To find the values of x and y.

We will use substitution method.

From (1) we get,

$y = -4-x$

We will put the value of y in (1) and we get,

$-x-4 = x^{2} -6x$

or, $x^{2} -5x+4= 0$

Now we will apply middle term factor method.

  $x^{2} -(4+1)x+4 = 0$

     $x^{2} -4x-x +4 = 0$

$x(x-4)-1(x-4) = 0$

       $(x-4)(x-1)= 0$

so, x = 4 and 1

Now,

Substitute x = 4 in (1) we get,

$y = -4-4 = -8$

And putting x = 1 in (1) we get,

$y = -4-1 = -5$

Hence, the solution of the given system of equation is (4,-8) and (1,-5)

Thus, Option A is the correct answer.