Answer:
The percent of callers are 37.21 who are on hold.
Step-by-step explanation:
Given:
A normally distributed data.
Mean of the data,
= 5.5 mins
Standard deviation,
= 0.4 mins
We have to find the callers percentage who are on hold between 5.4 and 5.8 mins.
Lets find z-score on each raw score.
⇒
...raw score,
=
⇒ Plugging the values.
⇒
⇒
For raw score 5.5 the z score is.
⇒
⇒
Now we have to look upon the values from Z score table and arrange them in probability terms then convert it into percentages.
We have to work with P(5.4<z<5.8).
⇒ 
⇒ 
⇒
⇒
and
.<em>..from z -score table.</em>
⇒ 
⇒
To find the percentage we have to multiply with 100.
⇒ 
⇒
%
The percent of callers who are on hold between 5.4 minutes to 5.8 minutes is 37.21
Answer:
The answer is option C
Step-by-step explanation:
sin C = opposite / hypotenuse
the opposite is 40
the Hypotenuse is 50
so
sin C = 40/50 = 4/5
Hope this helps you
1. True
2. False
3. False
4. True
Answer:
9) 4
10) p¹⁵/q⁹
Step-by-step explanation:
9)
As per the law of indices, (xᵃ)ᵇ=xᵃᵇ.
So divide 8 by 2 to get 4
10)
p(p⁻⁷q³)⁻²q⁻³
p(p¹⁴q⁻⁶)q⁻³ <em>(because (xᵃ)ᵇ=xᵃᵇ)</em>
pq⁻³(p¹⁴q⁻⁶)
p¹⁵q⁻⁹
p¹⁵/q⁹ <em>(because x⁻ᵃ =1 /xᵃ)</em>
Answer:
The bait is 14 feet below the water surface
Step-by-step explanation:
Here, we want to know the final position of the bait relative to the surface of the water.
Firstly, he starts with the bait at 2 feet below the water surface. The reels out the bait a further 19 feet, the new position of the bait relative to the water surface will be 2 + 19 = 21 feet
Now, he reels the bait back by 7 feet.
Thus, the new depth of the bait relative to the water surface will be 21-7 = 14 feet