Y = y(x) is the amount of bacteria after t hours.
Since we know the change is y WRT t is proportional to the amount of y:
dy/dt = my (m is some constant)
Solve for y using "Separation of Variables":
dy/y = mdt
Integrate both sides.
ln|y| = mt + C
|y| = e^(mt+C) = e^(mt) * e^C
y = ce^(mt) (where c = (+-)e^C)
Let's solve for the constant c by making use of the "initial values". We know at t=0 that y=6500.
6500 = ce^(m*0)
6500 = c
So now:
y = 6500e^(mt)
but we still need to solve for m somehow. Let's use the fact that the amount, y, doubles every Δt=7.3 hours.
At t=0:
y = 6500
So at t=7.3:
13000 = 6500e^(7.3m)
2 = e^(7.3m)
ln(2) = 7.3m
ln(2) / 7.3 = m
Substitute m:
y = 6500e^(ln(2)/7.3 * t)
We are interested in the amount of bacteria, y, after 5 hours (t=5):
y = 6500e^(ln(2)/7.3 * 5)
y = 10449.6 (approximately)
Answer:
2/5(x-1)-3/5(x+1)
Step-by-step explanation:
Of is always multiplication
Because you are multiplying an equation *x-1* you are going to put it into parenthesis.
Put the multiplying number(s) on the outside of the parenthesis to make it distributive property.
Less than always means minus
Therefore, the answer will be 2/5(x-1)-3/5(x+1)
Hoped this helped :)
Yes you did do this correctly
Answer:
4.5
Step-by-step explanation:
36 divided by 8 = 4.5. Maybe you meant 2 dozen, making it 24 divided by 8 = 3