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Feliz [49]
3 years ago
14

Find the product of:

Mathematics
1 answer:
Arturiano [62]3 years ago
6 0

(6t-n)2

6x (2)-n(2)

6 *2t-n (2)

12t-n(2)

12x-2y is your answer,good luck!

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If you watched a soccer match that lasted 2 hours and 20 minutes, how many total minutes did you watch
spayn [35]
1 hour = 60 minutes.
2 hours 20 minutes =  2 *60  + 20 = 120 + 20 = 140 minutes
7 0
4 years ago
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Which of the following represent the same level of precision? Check all that apply.
aniked [119]
Precision refers to the degree of significant figures, or basically how many numbers after the decimal. It <span>is the </span>number<span> of digits in a </span><span>number.
</span> 5.9 liters and 13.6 liters have the same precision (one number after the decimal).
<span>90 liters and 94 liters have the same precision (no decimals).

Correct answer: A and B, C and D</span>
7 0
3 years ago
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Chris can type 490 words in 7 min how many works can he type PER min <br> You get 14 points
amm1812
<h2>Answer: 70 words per min</h2><h2 /><h2>Step-by-step explanation: We just divided 490 by 7 to get how many words he can type for 1 min!</h2>

5 0
3 years ago
The width of a rectangle is 2x + 4 and the length of the
iren [92.7K]

Given:

Width of a rectangle = 2x+4

Length of the rectangle = 6x+12

To find:

The ratio of the width to the length.

Solution:

We need to find the ratio of the width to the length.

\text{Required Ratio}=\dfrac{\text{Width}}{\text{Length}}

Putting the given values, we get

\text{Required Ratio}=\dfrac{2x+4}{6x+12}

\text{Required Ratio}=\dfrac{2(x+2)}{6(x+2)}

\text{Required Ratio}=\dfrac{2}{6}

\text{Required Ratio}=\dfrac{1}{3}

\text{Required Ratio}=1:3

Therefore, the ratio of the width to the length is 1:3.

8 0
3 years ago
Find c, yenvelope(x,t), and ycarrier(x,t). express your answer in terms of a, k1, k2, x, t, ω1, and ω2. separate the three parts
steposvetlana [31]

Answer:

C,Y_{envelope}(x,t), Y_{carrier}(x,t)=2A, \cos ((k_1-k_2)x/2-(\omega_1 -\omega_2)t / 2 ) , \sin ((k_1+k_2)x / 2 - (\omega_1 +\omega_2)t / 2 )

Step-by-step explanation:

Given

Y_1(x,t)=A \sin(K_1x- \omega _1 t)\\\\Y_2(x,t)=A \sin(K_2x- \omega _2 t)

using a trigonometrical identity

sin p + sin q = 2 sin ( p+q/2) cos ( p-q/2)

and here the condition is

the choice is in between sinax and cosax

where a > b

so we get using above equation

C,Y_{envelope}(x,t), Y_{carrier}(x,t)=2A, \cos ((k_1-k_2)x/2-(\omega_1 -\omega_2)t / 2 ) , \sin ((k_1+k_2)x / 2 - (\omega_1 +\omega_2)t / 2 )

4 0
3 years ago
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