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Travka [436]
3 years ago
10

If seven consecutive numbers equal to 182, which one is the smallest?

Mathematics
2 answers:
Dafna1 [17]3 years ago
7 0

Answer:

23.

Step-by-step explanation:

My assumption: You mean when you add the numbers, they equal 182.

Let x be the smallest number. Then we are asked to solve the following equation:

x + (x + 1) + (x + 2) + (x + 3) + (x + 4) + (x + 5) + (x + 6) = 182.

Rearranging the equation gives us:

7x + 21 = 182 => x + 3 = 26 => x = 23.

So the smallest number is 23 (since our assumption was that x is the smallest number.

----

You could very well have stated that x was the middle number as a lot of cancellations would occur. That is:

(x - 3) + (x - 2) + (x - 1) + x + (x + 1) + (x + 2) + (x - 3) = 182.

7x = 182 => x = 26 so the smallest would be 26 - 3 = 23.

____ [38]3 years ago
4 0

Answer:

the seven consecutive numbers would be 23 24 25 26 27 28 29

Step-by-step explanation:


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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

Bayes Theorem:

Two events, A and B.

P(B|A) = \frac{P(B)*P(A|B)}{P(A)}

In which P(B|A) is the probability of B happening when A has happened and P(A|B) is the probability of A happening when B has happened.

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