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Readme [11.4K]
4 years ago
5

Which of the following documents cannot be created using the Microsoft® Word® application?

Computers and Technology
2 answers:
denis23 [38]4 years ago
7 0
The correct answer is C. Customer spreadsheet
san4es73 [151]4 years ago
7 0
(B) business flyer ....
You might be interested in
Use BlueJ to write a program that reads a sequence of data for several car objects from an input file. It stores the data in an
vaieri [72.5K]

Answer:

Java code is explained below

Explanation:

// Car.java

import java.util.Calendar;

public class Car {

  private String vin;

  private String make;

  private String model;

  private double cost;

  private int year;

  public Car(String vin, String make, String model, double cost, int year) {

      this.vin = vin;

      this.make = make;

      this.model = model;

      this.cost = cost;

      this.year = year;

  }

  public String getModel() {

      return model;

  }

  public double getCost() // returns car’s cost

  {

      return cost;

  }

  public String getMake() // returns car’s make

  {

      return make;

  }

  public boolean isExpensive() // returns true if car has cost above 30000 and

                                  // false

  // otherwise

  {

      if (cost > 30000)

          return true;

      else

          return false;

  }

  public boolean isAntique() // returns true if car’s has above 50 years, and

                              // false

  // otherwise

  {

      int cyear = Calendar.getInstance().get(Calendar.YEAR);

      if ((cyear-year) > 50)

          return true;

      else

          return false;

  }

  public String toString() // returns string with all car’s data in one line

  // separated by tabs.

  {

      return vin + "\t" + make + "\t" + model + " " + cost + "\t" + year;

  }

}

___________________________

// CarList.java

import java.io.File;

import java.io.FileNotFoundException;

import java.util.ArrayList;

import java.util.Scanner;

public class CarList {

  private ArrayList<Car> type;

  public CarList() throws FileNotFoundException {

      this.type = new ArrayList<Car>();

      Scanner sc1 = new Scanner(new File("inData.txt"));

      while (sc1.hasNextLine()) {

          String str = sc1.nextLine();

          String arr[] = str.split(" ");

          type.add(new Car(arr[0], arr[1], arr[2], Integer.parseInt(arr[3]),

                  Integer.parseInt(arr[4])));

      }

      sc1.close();

  }

 

  public void printList()

  {

      System.out.println("Displaying cars:");

      for(int i=0;i<type.size();i++)

      {

          System.out.println(type.get(i));

      }

  }

  public void printExpensiveCars()

  {

     

      System.out.println("List of expensive cars:");

      for(int i=0;i<type.size();i++)

      {

          if(type.get(i).isExpensive())

          {

              System.out.println(type.get(i));

          }

      }

  }

 

  public Car cheapestCar()

  {

      int cheapIndx=0;

      double min=type.get(0).getCost();

      for(int i=0;i<type.size();i++)

      {

      if(min>type.get(i).getCost())

      {

          min=type.get(i).getCost();

          cheapIndx=i;

      }

      }

      return type.get(cheapIndx);

  }

  public int countCarsWithModel(String model)

  {

      int cnt=0;

      for(int i=0;i<type.size();i++)

      {

          if(type.get(i).getModel().equals(model))

          {

              cnt++;

          }

      }

      return cnt;

  }

 

  public ArrayList<Car> antiqueCarList ()

  {

      ArrayList<Car> arl=new ArrayList<Car>();

      for(int i=0;i<type.size();i++)

      {

          if(type.get(i).isAntique())

          arl.add(type.get(i));

      }

      return arl;

  }

}

_________________________________

// TestCarList.java

import java.io.File;

import java.io.FileNotFoundException;

import java.util.ArrayList;

import java.util.Scanner;

public class TestCarList {

  public static void main(String[] args) throws FileNotFoundException {

      CarList cl = new CarList();

      cl.printList();

      cl.printExpensiveCars();

      ArrayList arl = cl.antiqueCarList();

      System.out.println("Displaying the AntiqueCar list:");

      for (int i = 0; i < arl.size(); i++) {

          System.out.println(arl.get(i));

      }

      System.out.println("Displaying the cheapest car :");

      System.out.println(cl.cheapestCar());

      System.out.println("No of Royal model Cars :"+ cl.countCarsWithModel("Royal"));

  }

}

____________________________

Output:

Displaying cars:

1234567CS2   Subaru   Impreza 27000.0   2017

1233219CS2   Toyota   Camry 31000.0   2010

9876543CS2   Ford   Mustang 51000.0   1968

3456789CS2   Toyota   Tercel 20000.0   2004

4567890CS2   Crysler   Royal 11000.0   1951

List of expensive cars:

1233219CS2   Toyota   Camry 31000.0   2010

9876543CS2   Ford   Mustang 51000.0   1968

Displaying the AntiqueCar list:

9876543CS2   Ford   Mustang 51000.0   1968

4567890CS2   Crysler   Royal 11000.0   1951

Displaying the cheapest car :

4567890CS2   Crysler   Royal 11000.0   1951

No of Royal model Cars :1

3 0
3 years ago
What method of the Math object can be used to return the largest value from the values that are passed to it?
miss Akunina [59]

Answer:

the Math.max() method

Explanation:

The java.lang.* package contains all the essential components needed for a JAVA program which involves numbers and all the operations done on the numericals.

The java.lang.math class contains all the methods needed to perform mathematical operations on numerical values.

All the methods in the question are discussed below with examples.  

Math.max() method

java.lang.Math.max(double/ int/ float a, double/ int/ float b)

This method returns the highest value from among the parameters passed to it.

The syntax for the above is  

Numbers can be integers, float and double or long. The return type is the same as the parameters.

Two values to be compared are passed as arguments and the higher value of them is returned.

This function also accepts negative integers as parameters.

Math.max(-9, -2);

Gives -2 as the output.

Math.max(0.34, 0.45)

Gives 0.45 as the output.

Math.ceil() method

java.lang.Math.ceil(double/ int/ float a)  

This method returns the nearest greater whole number for the given number.

Integer parameter returns an integer number.

Math.ceil(7);

Gives 7 as the output.

Decimal number will return the nearest higher integer.

Math.ceil(8.7);

Gives 9.0 as the output.

Math.ceil(-0.34)

Gives -0 as the output.

Math.pow() method

java.lang.Math.pow(double/ float/ int a, double/ float/ int b)

The above method returns the result of a raise to the power of b.

The first parameter is the base while the second parameter forms the exponent.

Math.pow( 2.3,  4.5 );

This calculates (2.3)^4.5.

Gives 42.44‬ as the output.

Math.pow( 2, 3 );

This calculates the value of 2^3.

Gives 8 as the output.

Math.abs() method  

java.lang.Math.abs(double a)

This method returns non-negative value of the numerical parameter passed to it. Absolute of a number does not changes its value but changes the sign of a negative number. It returns the positive or negation of the negative input number.

Math.abs(-0.1234)

Gives 0.1234 as the output.

Math.abs(12.34)

Gives 12.34 as the output.

These methods require java.lang.Math to be imported in the program.

7 0
4 years ago
As soon as I can, I will make a discord server for all brainly users. Would anyone like to join it once its set up? (only the di
Vesnalui [34]

Answer:me im bored ;p

5 0
4 years ago
Brainliest
alekssr [168]

Answer:

fair credit reporting act

6 0
3 years ago
____ storage is not recommended for long-term archiving because the storage media can degrade over time
Lunna [17]

Hard Drive is not recommended for long-term archiving because the storage media can degrade over time,

<h3>What type of storage is recommended for long term data retention?</h3>

The long method used to long-term retention is the use of cloud. Cloud-based are known to be a form of cold storage that is made up of intelligent storage software.

Note that Hard Drive is not a long term kind of storage in the above context and as such, PE storage is not recommended for long-term archiving because the storage media can degrade over time,

Learn more about storage from

brainly.com/question/1317328

#SPJ1

5 0
3 years ago
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