Answer:
hi your question lacks the necessary matrices attached to the answer is the complete question
1024 bytes
Explanation:
A) The minimum size of the cache to take advantage of blocked execution
The minimum size of the cache is approximately 1 kilo bytes
There are 128 elements( 64 * 2 ) in the preceding simple implementation and this because there are two matrices and every matrix contains 64 elements .
note: 8 bytes is been occupied by every element therefore the minimum size of the cache to take advantage of blocked execution
= number of elements * number of bytes
= 128 * 8 = 1024 bytes ≈ 1 kilobytes
Explanation:
A hub is used to send the message from one port to other ports.It does not know the specific address of the destination where the message needs to send.it works on Physical layer of the OSI model(layer 1).
A switch can handle data and it knows the specific address of the destination.A switch works on the data link Layer of the OSI model(layer 2).
B. training is the correct answer
Answer:
current_price = int(input("Enter the current price: "))
last_months_price = int(input("Enter the last month's price: "))
print("This house is $" + str(current_price))
print("The change is $" + str(current_price - last_months_price) + " since last month")
print("The estimated monthly mortgage is ${:.2f}".format((current_price * 0.051) / 12))
Explanation:
Ask the user to enter the current price and last month's price
Print the current price
Print the change in the price, subtract the last month's price from the current price
Print the estimated monthly mortgage, use the given formula to calculate, in required format
Answer:
d
Explanation:
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