Answer:
- Total Pressure = 1.019 atm
Explanation:
To solve this problem we use PV=nRT for both gases in their containers, in order to <u>calculate the moles of each one</u>:
645 Torr ⇒ 645 /760 = 0.85 atm
25°C ⇒ 25 + 273.16 = 298.16 K
0.85 atm * 1.40 L = n * 0.082 atm·L·mol⁻¹·K⁻¹ *298.16 K
n = 0.0487 mol O₂
1.13 atm * 0.751 L = n * 0.082 atm·L·mol⁻¹·K⁻¹ *298.16 K
n = 0.0347 mol N₂
Now we can <u>calculate the partial pressure for each gas in the new container</u>, because the number of moles did not change:
P(O₂) * 2.00 L = 0.0487 mol O₂ * 0.082 atm·L·mol⁻¹·K⁻¹ *298.16 K
P(O₂) = 0.595 atm
P(N₂) * 2.00 L = 0.0347 mol N₂ * 0.082 atm·L·mol⁻¹·K⁻¹ *298.16 K
P(N₂) = 0.424 atm
Finally we add the partial pressures of all gases to <u>calculate the total pressure</u>:
- Pt = 0.595 atm+ 0.424 atm = 1.019 atm
Answer:
The correct approach is "-2.67 kJ/mole". A further solution is described below.
Explanation:
The given values are:
No. of moles,
= 5.60 mol
Substance releases,
ΔH = 14.9 kJ
Now,
The ΔH in terms of kJ/mol will be:
= 
On putting the given values of ΔH, we get
= 
= 
Answer:
c.
Explanation:
It prevents consumers from purchasing unnecessary goods.
Answer:
Explanation:
Introducción. Dentro de la introducción, el investigador limita el estudio. Muestra los datos generales importantes y...
Hipótesis. La hipótesis consiste en una apreciación que el investigador hace en torno al problema. Se define como una...
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