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3 years ago

What's unique about this graph

Mathematics

2 answers:

viktelen [127]3 years ago

7 0

It’s an exponential graph. You can tell by the way the line is curved.

nataly862011 [7]3 years ago

4 0

It's equal on all sides no mater what

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Write as a monomial in standard form:f (–x^2y^3m)^5

laiz [17]

Answer:

Using the formula, write in standard form.

f,−x10y15m5

Step-by-step explanation:

7 0

3 years ago

PLEASE HELP!!! CALCULUS ASSIGNMENT

Serga [27]

Answer:

(d) $\displaystyle 12x^3 - 15x^2 + 2$

General Formulas and Concepts:

Algebra I

Functions
Function Notation

Calculus

Derivatives

Derivative Notation

Derivative Property [Addition/Subtraction]: $\displaystyle \frac{d}{dx}[f(x) + g(x)] = \frac{d}{dx}[f(x)] + \frac{d}{dx}[g(x)]$

Basic Power Rule:

f(x) = cxⁿ
f’(x) = c·nxⁿ⁻¹

Step-by-step explanation:

Step 1: Define

Identify

$\displaystyle y = 3x^4 - 5x^3 + 2x - 1$

Step 2: Differentiate

Basic Power Rule: $\displaystyle y' = 4(3x^{4 - 1}) - 3(5x^{3 - 1}) + 2x^{1 - 1} - 0$
Simplify: $\displaystyle y' = 4(3x^3) - 3(5x^2) + 2$
Multiply: $\displaystyle y' = 12x^3 - 15x^2 + 2$

Topic: AP Calculus AB/BC (Calculus I/I + II)

Unit: Derivatives

Book: College Calculus 10e

3 0

3 years ago

Read 2 more answers

F the point T is between the points B and N, then which of the following is true?

valentina_108 [34]

Assuming T, B and N are all on the same line, then we can say

BT + TN = BN

which is the segment addition postulate.

Subtract TN from both sides to get
BT + TN = BN
BT + TN - TN = BN - TN
BT = BN - TN
BN - TN = BT

Which is what choice C is saying. Therefore the answer is choice C.

3 0

3 years ago

Read 2 more answers

Convert x2 + y2 -4x = 0 to polar form.

Bingel [31]

Answer:

$r(r-4\cos \theta)=0$

Step-by-step explanation:

We are given the following equation:

$x^2 + y^2 -4x = 0$

We have to convert it into polar form.

We put

$x = r \cos \theta\\y = r\sin \theta$

Putting values, we get:

$x^2 + y^2 -4x = 0\\(r\cos \theta)^2 + (r\sin \theta)^2 - 4(r\cos \theta) = 0\\r^2(\cos^2 \theta + \sin^2 \theta) - 4r\cos \theta = 0\\r^2 - 4r\cos \theta = 0\\r(r-4\cos \theta)=0$

is the required polar form.

7 0

2 years ago

Can anyone answer these 4? if so ill give 40 points. please show work!! and no long division please. , thanks!

dolphi86 [110]

54x89=4806

123x85=10,455

64x15=960

264x14=3,696

6 0

2 years ago