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3 years ago

What does x equal in x plus 6 =2x plus 3

Mathematics

2 answers:

Anuta_ua [19.1K]3 years ago

4 0

Answer:

$x = 3$

Step-by-step explanation:

$x + 6 = 2x + 3 \\ subtract \: 2x \: from \: both \: sides \\ \\ -1x + 6 = 3 \\ subtract \: 6 \: from \: both \: sides \\ \\ - 1x = - 3 \\ divide \: both \: sides \: by \: - 1 \\ \\ x = 3$

fenix001 [56]3 years ago

4 0

Answer:

Step-by-step explanation:

x + 6= 2x + 3

what you would do to find the answer is first subtract the coeffcient 2 on both sides of the equation. ( Subtract the 2 under 2x for the right side of the equation and subtract 2 under the x on the left side. ) Then you would subtract 6 on both sides. (subtract 6 under the 6 on the left side of the equation and subtract 6 under the number 3 on the right side of the equation)

so that would give you -x = -3 However you would have to eliminate the x on the right side of the equation and so you would divide positive x (also known as 1x) on both sides. -1x/-1 = -1 and -3/-1 = 3

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Find the range and interquartile range for the data represented by the box plot.

Anarel [89]

Given:

Given that the data are represented by the box plot.

We need to determine the range and interquartile range.

Range:

The range of the data is the difference between the highest and the lowest value in the given set of data.

From the box plot, the highest value is 30 and the lowest value is 15.

Thus, the range of the data is given by

Range = Highest value - Lowest value

Range = 30 - 15 = 15

Thus, the range of the data is 15.

Interquartile range:

The interquartile range is the difference between the ends of the box in the box plot.

Thus, the interquartile range is given by

Interquartile range = 27 - 18 = 9

Thus, the interquartile range is 9.

3 0

3 years ago

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Suppose that the proportions of blood phenotypes in a particular population are as follows: A B AB O 0.48 0.13 0.03 0.36 Assumin

Serggg [28]

Answer:

P(O and O) =0.1296

P=0.3778

Step-by-step explanation:

Given that

blood phenotypes in a particular population

A=0.48

B=0.13

AB=0.03

O=0.36

As we know that when A and B both are independent that

P(A and B)= P(A) X P(B)

The probability that both phenotypes O are in independent:

P(O and O)= P(O) X P(O)

P(O and O)= 0.36 X 0.36 =0.1296

P(O and O) =0.1296

The probability that the phenotypes of two randomly selected individuals match:

Here four case are possible

P=P(A and A)+P(B and B)+P(AB and AB)+P(O and O)

P=0.48 x 0.48 + 0.13 x 0.13 + 0.03 x 0.03 + 0.36 x 0.36

P=0.3778

7 0

3 years ago

Can someone help me with number 10, 11, 12, 15, and 16 I don’t understand them thanks

yanalaym [24]

10)

$10^2-48:6+25*3=100-8+75=167$

11)

$8(\frac{16}{4} )+2^2-11*3=32+4-33=3$

12)

$(\frac{6}{3} +4)^2:4*7=(2+4)^2:4*7=6^2:4*7=36:4*7=9*7=63$

13) (your answer is incorrect)

$5(9-4)^2-3^2=5*5^2-3^2=5*25-9=125-9=116$

14) (your answer is incorrect)

$5^2-2^2*4^2-12=25-4*16-12=25-64-12=-51$

15)

$(\frac{50}{5^2} )^2:4=(\frac{50}{25} )^2:4=2^2:4=4:4=1$

16)

$\frac{24+32+30+28}{2}$ -expression to represent this situation

$\frac{24+32+30+28}{2}=\frac{114}{2}=57$

Answer: In 1 group 57 students

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P.S. Hello from Russia :^)

4 0

2 years ago

Would appreciate any help!! :D

Salsk061 [2.6K]

73+112+90=275
360-275=85
the angle of x is 85 degrees
(pls mark brainliest)

6 0

2 years ago

In a shipment of airplane parts 3% are known to be defective . If 15 parts are found to be defective how many parts are in the s

marissa [1.9K]

If 3% out of 100% are defective it would be 3 out of every 100, and 3 multiplied by 5 is 15. Then you multiply 100 by 5 and its 500 so out of 500 parts 15 would be defective

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3 years ago

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