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vesna_86 [32]
4 years ago
12

Find the center of the circle whose equation is 3x² + 3y² = 75.

Mathematics
2 answers:
alexdok [17]4 years ago
5 0
3x^2 + 3y^2 = 75 

Dividing through by 3 we get

x^2 + y^2 = 25 

The center is at (0,0) answer
tino4ka555 [31]4 years ago
3 0

Answer:

Center = (0,0)

Step-by-step explanation:

The standard form of a circle is

(x-h)^2+(y-k)^2=r^2           ..... (1)

where, (h,k) is the center of the circle and r is radius.

The given equation is

3x^2+3y^2=75

Divide both sides by 3.

x^2+y^2=25

x^2+y^2=5^2           ..... (2)

On comparing (1) and (2) we get

h=0, k=0, r=5

Therefore, the center of the circle is (0,0) and radius of the circle is 5.

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