Answer:
The first step is to multiply by a power of 10, so the divisor is a whole number.
Step-by-step explanation:
Hello :
<span>g(x) = 5x² - 50x + 128
= 5(x²-10x +128/5)
= 5 (x²-10x+5²-5² +128/5)
= 5 ((x-5)² +128/5 -125/5)
y = 5 ((x-5)² - 3/5)
y= 5(x-5)² +3.....vertex form
the vertex is : (5,3)</span>
Answer:
Yes.
Step-by-step explanation:
( I will have to replace all 
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with 
)
So the answer is yes.
Answer:
B, C
Step-by-step explanation:
Since y=0, you are looking for equations such that 10 times the coefficient of x is the constant in the equation.
a) 5·10 ≠ 15
b) 2·10 = 20 . . . . select this one
c) 10 = 10 . . . . select this one
d) 3·10 ≠ 13
e) 4·10 ≠ 20
f) 6·10 ≠ 50
