$e\cdot e^x -e^{-2}=-2$
$\implies e^{x+1}=e^{-2}-2$
note that RHS is negative. (because e with negative exponent is less than 1)
and LHS is always positive.
so there cannot be any solution
There are three steps:<span>
1.)Rearrange the equation so "y" is on the left and everything else on the right.
2.)Plot the "y=" line (make it a solid line for y≤ or y≥, and a dashed line for y< or y>)
<span>
3.)Shade above the line for a "greater than" (y> or y≥) or below the line for a "less than" (y< or y≤).</span></span>
To get this answer you would have to have a pace calculator!
Answer:
ur correct u got it.
Step-by-step explanation:
Answer:
−36+4
Step-by-step explanation:
