Although they are the same variable, you cannot add two variables raised to different powers. 3x^1 + 5x^2 cannot work, but 3x^2 + 5x^2 can. Also, if you are multiplying them, they would combine to be 15x^3, as 3 and 5 (The coefficients) multiply together and x^2 times x^1 = x^3.
I hope that helps.
Answer:
-2y + 3 = 0
Step-by-step explanation:
x - 6y - 9 = 0
-6y - 9 = -x subtract x from both sides
6y + 9 = x divide both sides by -1
x = 8y + 6
6y + 9 = 8y + 6 replace x with 6y + 9
-2y + 9 = 6 subtract 8y from both sides
-2y + 3 = 0 subtract 6 from both sides
Brenda has to take out the trash more than 4 times to have more than $50.
Step-by-step explanation:
Given,
Amount Brenda already have = $30
Amount she gets each time for throwing trash = $5
Amount she wants to have = More than $50
Let,
x be the number of times she throws trash.
Amount for throwing trash * Number of times trash thrown + Amount already have > Amount she wants to have

Dividing both sides by 5

Brenda has to take out the trash more than 4 times to have more than $50.
Keywords: variable, inequality
Learn more about variables at:
#LearnwithBrainly
24÷3=8
There will be eight players on each team.