Answer:
Step-by-step explanation:
We want to rewrite
in the form that would most easily help you identfiy the zeros of the function.
This the same as writing in factored form.
Factor by grouping:
Factor further to get:
Answer:
155 lbs.
Step-by-step explanation:
69.75 g of protein divided by 0.45= 155
Answer:
Step-by-step explanation:
<u>Given</u>
- Line L with
- y-intercept = 3
- Points (a, a) and (2a, 12)
<u>The slope is</u>
- m = (y2 - y1)/(x2 - x1)
- = (12 - a)/(2a - a)
- = (12 - a)/a
Answer:
Point Critical point
Q (2,0) local minimum
R (-2,1) Saddle
S (2,-1) local maximum
T ( -2,-1) Saddle
O ( -2,0) Saddle
Step-by-step explanation: INCOMPLETE ANSWER INFORMATION ABOUT THE POINTS ARE RARE
f(x,y) = x³ +y⁴ - 6x -2y² +3
df/dx = f´(x) = 3x² -6x
df/dxdx = f´´(xx) = 6x
df/dy = f´(y) = -4y
df/dydy = 4
df/dydx = df/dxdy = 0
df/dydy = f´´(yy)
D = [ df/dxdx *df/dydy] - [df/dydx]²
D = (6x)*4 - 0
D = 6*2*4 D > 0 and the second derivative on x is 6*2 = 12
so D > 0 and df/dxdx >0 there is a local minimum in P
Q(2,1)
D = (6*2)*4 D>0 and second derivative on x is 6*2
The same condition there is a minimum in Q
R ( -2,1)
D = 6*(-2)*4 = -48 D< 0 there is a saddle point in R
S (2,-1)
D = 6*2*4 = 48 D > 0 and df/dxdx = 6*-1 = -6
There is a maximum in S
T ( -2,-1)
D = 6*(-2)*(4) = -48 D<0 there is a saddle point in T
O ( -2,0)
D = 6*(-2)*4 = -48 D<0 there is a saddle point in O
I assume your "reasons" mean "roots" or "zeros"
if 3 is a root, plug x=3 in the equation, you can find n:
3²+(n-1)*3+6=0
3(n-1)=-15
n-1=-5
n=-4
Plug n=-4 in the original equation: x²-5x+6=0
factor: (x-3)(x-2)=0
x=3, which we already know
or x=2, which is the value of m+4
m+4=2
m=-2
