-7 2/3 + (-5 1/2) + 8 3/4

74 students were chosen from a local university to participate in a study. Every student attending the university had an equal p

Gala2k [10]

The answer is : Random Selection

8 0

3 years ago

Read 2 more answers

A total of 2n cards, of which 2 are aces, are to be randomly divided among two players, with each player receiving n cards. Each

klasskru [66]

Answer:

$P(X_s^c|X_F) =0.2$

$P(X_s^c|X_F) =0.31$

$P(X_s^c|X_F) =0.331$

Step-by-step explanation:

From the given information:

Let represent $X_F$ as the first player getting an ace

Let $X_S$ to be the second player getting an ace and

$\sim X_S$ as the second player not getting an ace.

So;

The probabiility of the second player not getting an ace and the first player getting an ace can be computed as;

$P(\sim X_S| X_F) = 1 - P(X_S|X_F)$

$P(X_S|X_F) = \dfrac{P(X_SX_F)}{P(X_F)}$

Let's determine the probability of getting an ace in the first player

i.e

$P(X_F) = 1 - P(X_F^c)$

$= 1 -\dfrac{(^{2n-2}_n)}{(^{2n}_n)}}$

$= 1 - \dfrac{n-1}{2(2n-1)}$

$= \dfrac{3n-1}{4n-2} --- (1)$

To determine the probability of the second player getting an ace and the first player getting an ace.

$P(X_sX_F) = \text{ (distribute aces to both ) and (select the left over n-1 cards from 2n-2 cards}$ $P(X_sX_F) = \dfrac{2(^{2n-2}C_{n-1})}{^{2n}C_n}$

$P(X_sX_F) = \dfrac{n}{2n -1}---(2)$

$P(X_s|X_F) = \dfrac{2}{1}$

$P(X_s|X_F) = \dfrac{2n}{3n -1}$

Thus, the conditional probability that the second player has no aces, provided that the first player declares affirmative is:

$P(X_s^c|X_F) = 1- \dfrac{2n}{3n -1}$

$P(X_s^c|X_F) = \dfrac{n-1}{3n -1}$

Therefore;

for n= 2

$P(X_s^c|X_F) = \dfrac{2-1}{3(2) -1}$

$P(X_s^c|X_F) = \dfrac{1}{6 -1}$

$P(X_s^c|X_F) = \dfrac{1}{5}$

$P(X_s^c|X_F) =0.2$

for n= 10

$P(X_s^c|X_F) = \dfrac{10-1}{3(10) -1}$

$P(X_s^c|X_F) = \dfrac{9}{30 -1}$

$P(X_s^c|X_F) = \dfrac{9}{29}$

$P(X_s^c|X_F) =0.31$

for n = 100

$P(X_s^c|X_F) = \dfrac{100-1}{3(100) -1}$

$P(X_s^c|X_F) = \dfrac{99}{300 -1}$

$P(X_s^c|X_F) = \dfrac{99}{299}$

$P(X_s^c|X_F) =0.331$

8 0

3 years ago

Help sorry for blur

liq [111]

When the 2D figure is in the place then u rotate it even more

5 0

3 years ago

fomenos

Answer:

Two figures are similar if the figures have the same shape but different sizes.

Then if we have two figures X and X'

Such that one dimension of X is D, the correspondent dimension on X' will be:

D' = k*D

Such that k is the scale factor that relates the figures.

1:k

Because all the dimensions will be rescaled by the same scale factor k, we can conclude that any surface on X will be related to the same surface in X' by:

S' = k^2*S

then the ratio of the surfaces is:

1:k^2

While the relation between the volumes will be:

V' = k^3*V

Here the ratio is:

1:k^3

Ok, in this case we have two cylinders

We know that the ratio between the base area ( a surface) is:

9:25

a) We want to find the ratio: curved surface area of A : curved surface area of B

Because again we have a surface area, the ratio should be exactly the same as before, 9:25

b) height of A : height of B

In this case, we have a single dimension.

Because in the rescaling of a surface we need to use k^2, then we can conclude that the ratios:

9:25

is related to k^2

Then the ratio, in this case, is given by applying the square root to both sides of the previous ratio, so we get:

√9:√25

3:5

This is the ratio of the heights.

Also from this we could get the value of k, that is the right value when we leave the left value equal to 1, we can get that if we divide both sides by 3.

(3/3):(5/3)

1:(5/3)

Then:

k = 5/3

7 0

3 years ago

How do I find the simplest form,for this problem 4-2(3+6)+2-2=

levacccp [35]

Try using PEMDAS,
Parentheses
Exponents
Multiplication
Division
Addition
Subtraction

So just do the problem in that order.

5 0

4 years ago