you need to learn ill give you the answer but remember it so you can learn
Answer:
c
Step-by-step explanation:
1.2 0.4. NS. Pure error 15 42.0 2.8. No significant lack of fit. 3b. Yes. 4a. ... D. First note that the sum of squares function for the no-intercept model is ... {2: (Xi - X)(Yi - Y)F _ SS(Rlho) _ 2 ... The plot of the residuals against Y indicates the omission of the f30 term in the model. 4. ... C. A is 2 X 3, b is 2 X 1, C is 2 X 2, D is 3 X 3.
Answer:
She should use 1/2 cup of chocolate chips.
Step-by-step explanation:
If she uses 2 cups for 8 people, that means
2 x 4 =8
So, all you have to do is,
? x 4 = 2
0.5 x 4 = 2
0.5 = 1/2
She should use 1/2 cup of chocolate chips
Answer:
![\large\boxed{Q1:\ x=2\ or\ x=5}\\\boxed{Q2:\ x=1-\sqrt{21}\ or\ x=1+\sqrt{21}}](https://tex.z-dn.net/?f=%5Clarge%5Cboxed%7BQ1%3A%5C%20x%3D2%5C%20or%5C%20x%3D5%7D%5C%5C%5Cboxed%7BQ2%3A%5C%20x%3D1-%5Csqrt%7B21%7D%5C%20or%5C%20x%3D1%2B%5Csqrt%7B21%7D%7D)
Step-by-step explanation:
![\text{Use the quadratic formula:}\\\\ax^2+bx+c=0\\\\\text{If}\ b^2-4ac0,\ \text{then the equation has two solutions}\ x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}\\\\==========================================](https://tex.z-dn.net/?f=%5Ctext%7BUse%20the%20quadratic%20formula%3A%7D%5C%5C%5C%5Cax%5E2%2Bbx%2Bc%3D0%5C%5C%5C%5C%5Ctext%7BIf%7D%5C%20b%5E2-4ac%3C0%2C%5C%20%5Ctext%7Bthen%20the%20equation%20has%7D%5C%20%5Cbold%7Bno%5C%20solution%7D%5C%5C%5C%5C%5Ctext%7BIf%7D%5C%20b%5E2-4ac%3D0%2C%5C%20%5Ctext%7Bthen%20the%20equation%20has%20one%20solution%7D%5C%20x%3D%5Cdfrac%7B-b%7D%7B2a%7D%5C%5C%5C%5C%5Ctext%7BIf%7D%5C%20b%5E2-4ac%3E0%2C%5C%20%5Ctext%7Bthen%20the%20equation%20has%20two%20solutions%7D%5C%20x%3D%5Cdfrac%7B-b%5Cpm%5Csqrt%7Bb%5E2-4ac%7D%7D%7B2a%7D%5C%5C%5C%5C%3D%3D%3D%3D%3D%3D%3D%3D%3D%3D%3D%3D%3D%3D%3D%3D%3D%3D%3D%3D%3D%3D%3D%3D%3D%3D%3D%3D%3D%3D%3D%3D%3D%3D%3D%3D%3D%3D%3D%3D%3D%3D)
![\bold{Q1}\\\\x^2-7x+10=0\\\\a=1,\ b=-7,\ c=10\\\\b^2-4ac=(-7)^2-4(1)(10)=49-40=9>0\\\\\sqrt{b^2-4ac}=\sqrt9=3\\\\x_1=\dfrac{-(-7)-3}{2(1)}=\dfrac{7-3}{2}=\dfrac{4}{2}=2\\\\x_2=\dfrac{-(-7)+3}{2(1)}=\dfrac{7+3}{2}=\dfrac{10}{2}=5\\\\========================================](https://tex.z-dn.net/?f=%5Cbold%7BQ1%7D%5C%5C%5C%5Cx%5E2-7x%2B10%3D0%5C%5C%5C%5Ca%3D1%2C%5C%20b%3D-7%2C%5C%20c%3D10%5C%5C%5C%5Cb%5E2-4ac%3D%28-7%29%5E2-4%281%29%2810%29%3D49-40%3D9%3E0%5C%5C%5C%5C%5Csqrt%7Bb%5E2-4ac%7D%3D%5Csqrt9%3D3%5C%5C%5C%5Cx_1%3D%5Cdfrac%7B-%28-7%29-3%7D%7B2%281%29%7D%3D%5Cdfrac%7B7-3%7D%7B2%7D%3D%5Cdfrac%7B4%7D%7B2%7D%3D2%5C%5C%5C%5Cx_2%3D%5Cdfrac%7B-%28-7%29%2B3%7D%7B2%281%29%7D%3D%5Cdfrac%7B7%2B3%7D%7B2%7D%3D%5Cdfrac%7B10%7D%7B2%7D%3D5%5C%5C%5C%5C%3D%3D%3D%3D%3D%3D%3D%3D%3D%3D%3D%3D%3D%3D%3D%3D%3D%3D%3D%3D%3D%3D%3D%3D%3D%3D%3D%3D%3D%3D%3D%3D%3D%3D%3D%3D%3D%3D%3D%3D)
![\bold{Q2}\\x^2-2x=20\qquad\text{subtract 20 from both sides}\\\\x^2-2x-20=0\\\\a=1,\ b=-2,\ c=-20\\\\b^2-4ac=(-2)^2-4(1)(-20)=4+80=84>0\\\\\sqrt{b^2-4ac}=\sqrt{84}=\sqrt{4\cdot21}=\sqrt4\cdot\sqrt{21}=2\sqrt{21}\\\\x_1=\dfrac{-(-2)-2\sqrt{21}}{2(1)}=\dfrac{2-2\sqrt{21}}{2}=1-\sqrt{21}\\\\x_2=\dfrac{-(-2)+2\sqrt{21}}{2(1)}=\dfrac{2+2\sqrt{21}}{2}=1+\sqrt{21}](https://tex.z-dn.net/?f=%5Cbold%7BQ2%7D%5C%5Cx%5E2-2x%3D20%5Cqquad%5Ctext%7Bsubtract%2020%20from%20both%20sides%7D%5C%5C%5C%5Cx%5E2-2x-20%3D0%5C%5C%5C%5Ca%3D1%2C%5C%20b%3D-2%2C%5C%20c%3D-20%5C%5C%5C%5Cb%5E2-4ac%3D%28-2%29%5E2-4%281%29%28-20%29%3D4%2B80%3D84%3E0%5C%5C%5C%5C%5Csqrt%7Bb%5E2-4ac%7D%3D%5Csqrt%7B84%7D%3D%5Csqrt%7B4%5Ccdot21%7D%3D%5Csqrt4%5Ccdot%5Csqrt%7B21%7D%3D2%5Csqrt%7B21%7D%5C%5C%5C%5Cx_1%3D%5Cdfrac%7B-%28-2%29-2%5Csqrt%7B21%7D%7D%7B2%281%29%7D%3D%5Cdfrac%7B2-2%5Csqrt%7B21%7D%7D%7B2%7D%3D1-%5Csqrt%7B21%7D%5C%5C%5C%5Cx_2%3D%5Cdfrac%7B-%28-2%29%2B2%5Csqrt%7B21%7D%7D%7B2%281%29%7D%3D%5Cdfrac%7B2%2B2%5Csqrt%7B21%7D%7D%7B2%7D%3D1%2B%5Csqrt%7B21%7D)