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Irina18 [472]
1 year ago
13

A random group of 100 male business managers was gathered together. Of them, 81 were wearing ties. What percent is this? Answer

this with a number and the "%" symbol.
Mathematics
1 answer:
kvv77 [185]1 year ago
5 0

Given:group of 100 male business managers was gathered together. Of them, 81 were wearing ties.

Find: percentage of this

Explanation: percentage of persons whose wearing ties are equal to

\frac{81}{100}\times100=81\%

Final answer: 81 percent is required answer.

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Find the values of the six trigonometric functions of 0
Leni [432]

Step-by-step explanation:

sin theta = 12/13

cos theta = 5/13

tan theta = 12/5

cosec theta = 13/12

sec theta = 13/5

cot theta = 5/12

8 0
3 years ago
7. (5 + 4 – 2) х (-2) = ?<br> А. 14<br> В. -22<br> с. -14<br> D.22
Talja [164]
Step 1. (5+4-2)x(-2)
Step 2. (7)x(-2)
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7 0
3 years ago
The number of accidents per week at a hazardous intersection varies with mean 2.2 and standard deviation of 1.4. The distributio
posledela

Answer:

Approximate probability that \overline{X} is less than 2 = 0.1515

Step-by-step explanation:

Given -

Mean (\nu ) = 2.2

Standard deviation (\sigma  ) = 1.4

Sample size ( n ) = 52

Let  \overline{X} be the mean of accidents per week at the intersection during one year (52 weeks) .

probability that \overline{X} is less than 2 =

P(\overline{X}< 2)  = P(\frac{\overline{X} - \nu }{\frac{\sigma }{\sqrt{n}}}< \frac{2 - 2.2 }{\frac{1.4}{\sqrt{52}}})   Putting (Z =\frac{\overline{X} - \nu }{\frac{\sigma }{\sqrt{n}}})

                 = P(Z< - 1.03)    ( Using Z table )

                 = 0.1515

7 0
3 years ago
Determine the area of a square with side length 2√7 in.
Ainat [17]

Answer:

28 inch

Step-by-step explanation:

The length of all four sides of square is equal.

The formula used for finding the area of square is:

Area = (Length) × (Length)

Thus, the Area of square whose length is 2√7 is:

Area = 2√7 × 2√7

⇒ Area = 4 × 7 = 28 inch.

3 0
3 years ago
A student earned grades of Upper AA​, Upper DD​, Upper AA​, Upper CC​, and Upper BB. Those courses had the corresponding numbers
dmitriy555 [2]

Answer:

  • The grade point average is 2.92
  • The student didn't make the​ Dean's list because the​ student's GPA is less than 3.0

Step-by-step explanation:

  • I take the grades as A,D,A,C,B not AA​,DD​,AA​,CC​,BB.
  • I take numbers of credit hours as 4,2,2,3,1 not as 44​, 22​, 22​, 33​, and 11.

Since quality points to letter grades are A=​4; B=​3; C=​2; D=​1; F=0, weighted mean is the sum of the qulity points times corresponding credit hours divided by the total credit hours:

\frac{(4*4) + (1*2) + (4*2) + (2*3) + (3*1)}{12} ≈ 2.92

Since 2.92<3.0, the student is not in Dean's list.

8 0
3 years ago
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