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Irina18 [472]
1 year ago
13

A random group of 100 male business managers was gathered together. Of them, 81 were wearing ties. What percent is this? Answer

this with a number and the "%" symbol.
Mathematics
1 answer:
kvv77 [185]1 year ago
5 0

Given:group of 100 male business managers was gathered together. Of them, 81 were wearing ties.

Find: percentage of this

Explanation: percentage of persons whose wearing ties are equal to

\frac{81}{100}\times100=81\%

Final answer: 81 percent is required answer.

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2x4^2=24+97^10=A<br> {A+B=c*}
Sunny_sXe [5.5K]
The answer is 27 bc abc’s have 27 letters but if u do it another way u will get 69 if I get 69 than your girl will be appreciative and love you more so the answer is sex is one of the key things to a relationship how this helps:)
3 0
3 years ago
– 5 | 3 z + 8| –5 = -20​
olchik [2.2K]

I'm assuming you want to solve for  z  :)

By simplifying both sides of the equation, then isolating the variable.

Exact form:

z= -5/3 , - 11/3

Mixed number form:

z=  −1  2/3  ,  −3  2/3

8 0
2 years ago
Read 2 more answers
What is the disturbited property of (-2.5)(3-8y)
Mars2501 [29]

<u><em>Answer: =-7.5+20y</em></u>

Step-by-step explanation:

distributive property: a(b+c)=ab+ac

a=-2.5, b=3, c=8y

-2.5*3-(-2.5)*8y

3(-2.5)-8(-2.5)y

simplify by equation.

3(-2.5)-8(-2.5)y=-7.5+20y

=-7.5+20y

Hope this helps!

Thanks!

Have a great day!

3 0
3 years ago
On Roberto's shelf there are:
Sergio039 [100]

Answer:

he would have a 20% chance he will pick a history book, so in decimal form it would be .2

Step-by-step explanation:

7+6+4+3=20

20*5=100

5*4=20

5 0
2 years ago
Ian is a phycologist interested in determining the proportion of algae samples from a local rivulet that belonged to a particula
pickupchik [31]

Answer: 16590

Step-by-step explanation:

The formula we use to find the sample size is given by :-

, where p = prior estimate of population proportion.

z^*= Critical z-value (Two- tailed)

E= Margin of error .

Let p be the population proportion of cyanobacteria.

Given : E = 0.01

Critical value for 99% confidence interval : z^*=2.576

If Ian does not want to rely on previous knowledge , then we assume p=0.5 because the largest standard error is at p=0.5.

Now, the required sample size = n=0.5(1-0.5)(\frac{2.576}{0.01})^2

n=0.25(257.6)^2=0.25(66357.76)=16589.44\approx16590

Required sample size = 16590

5 0
2 years ago
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