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According to the information given, the absolute value inequality that can be used to assess which pens are tolerable is:
The <em>absolute value</em> function measures the <u>distance of a point to the origin</u>, and is defined by:
The weight must be of 10g, with a tolerance of 2g, which means that the <u>absolute value of the difference between the weight w and 10g must be of at most 2g</u>, hence the inequality is:
To learn more about absolute value inequalities, you can take a look at brainly.com/question/24005819
Answer:
And replacing we got:
So we are going to expect about 2,85 automobiles for this case.
Step-by-step explanation:
For this case we define the random variable X as "number of automobiles lined up at a Lakeside Olds dealer at opening time (7:30 a.m.)" and we know the distribution for X is given by:
X 1 2 3 4
P(X) 0.05 0.30 0.40 0.25
The expected value of a random variable X is the n-th moment about zero of a probability density function f(x) if X is continuous, or the weighted average for a discrete probability distribution, if X is discrete
For this case we can calculate the epected value with this formula:
And replacing we got:
So we are going to expect about 2,85 automobiles for this case.