PLSSS HELPPP!!!<br> i don’t know

DanielleElmas [232]

Answer:

hope this helps

Step-by-step explanation:

so first you would convert the 3 3/8 to a improper fraction which would be 27/8 the n you would multiply the 27 by 2 and the 8 by 1 then 27 and you would get 64/8 and 8 divided by 64 is 8 so the volume is 8

the dashes are fractions.

7 0

3 years ago

Which of the following statements uses the multiplicative identity?

Dahasolnce [82]

That would be A. -8 x 1 = -8

8 0

3 years ago

Read 2 more answers

I need help with number 20. Please be sure to explain. Thank You! There is a picture attached btw.

yan [13]

He should have added 1 to both sides to make the -1 on the right go to 0.
Then it would be 0 + m = -16 + 1 = -15
You can check your work by adding -1 and -15, which does in fact equal -16.
Hope this helped :)

3 0

4 years ago

Solve the system of equations by the addition method.

Eva8 [605]

$\left \{ {{\frac{x}{2}-y=7 } \atop {-\frac{x}{7}+\frac{2y}{7}= -2 }} \right. \left \{ {{\frac{x}{2}.2-2y=2.7} \atop {-\frac{x}{7}.7+\frac{2y}{7}.7= -2.7}} \right. \left \{ {{x-2y=14} \atop {-x+2y=-14}} \right. \left \{ {{0x=0} \atop {y={\frac{x}{2}-7}} \right.$

ANSWER: B

ok done. Thank to me :>

8 0

3 years ago

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A random sample of 49 measurements from one population had a sample mean of 15, with sample standard deviation 5. An independent

kotykmax [81]

Answer:

Comparing the p value with the significance level $\alpha=0.01$ we see that $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, and the difference between the two groups is significantly different.

Step-by-step explanation:

$\bar X_{1}=15$ represent the mean for sample 1

$\bar X_{2}=18$ represent the mean for sample 2

$s_{1}=5$ represent the sample standard deviation for 1

$s_{f}=6$ represent the sample standard deviation for 2

$n_{1}=49$ sample size for the group 2

$n_{2}=64$ sample size for the group 2

$\alpha=0.01$ Significance level provided

t would represent the statistic (variable of interest)

Concepts and formulas to use

We need to conduct a hypothesis in order to check if the difference in the population means, the system of hypothesis would be:

Null hypothesis: $\mu_{1}-\mu_{2}=0$

Alternative hypothesis: $\mu_{1} - \mu_{2}\neq 0$

We don't have the population standard deviation's, so for this case is better apply a t test to compare means, and the statistic is given by:

$t=\frac{(\bar X_{1}-\bar X_{2})-\Delta}{\sqrt{\frac{s^2_{1}}{n_{1}}+\frac{s^2_{2}}{n_{2}}}}$ (1)

And the degrees of freedom are given by $df=n_1 +n_2 -2=49+64-2=111$

t-test: Is used to compare group means. Is one of the most common tests and is used to determine whether the means of two groups are equal to each other.

With the info given we can replace in formula (1) like this:

$t=\frac{(15-18)-0}{\sqrt{\frac{5^2}{49}+\frac{6^2}{64}}}}=-2.897$

P value

Since is a bilateral test the p value would be:

$p_v =2*P(t_{111}$

Comparing the p value with the significance level $\alpha=0.01$ we see that $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, and the difference between the two groups is significantly different.

7 0

3 years ago

PLSSS HELPPP!!! i don’t know