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3 years ago

The complement of 17% is

Mathematics

2 answers:

ikadub [295]3 years ago

6 0

38% :)))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))

Allushta [10]3 years ago

5 0

Answer:

73%.

Step-by-step explanation:

Let x be the complement of 17%.

We are asked to find the complement of 17%.

We know that two angles are complementary when they add up-to 90 degrees. So we can set an equation as:

$17\%+x=90\%$

$17\%-17\%+x=90\%-17\%$

$17\%-17\%+x=73\%$

Therefore, the complement of 17% is 73%.

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If an arrow is shot upward on Mars with a speed of 68 m/s, its height in meters t seconds later is given by

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Answer:

(a) dy/dt = 68 - 3.72t

(b) 64.28m/s

Step-by-step explanation:

Given y = 68t - 1.86t²

Average Speed is rate of chance of distance with respect to time. Written as dy/dt

To obtain dy/dt, we differentiate y with respect to t, doing that, we have

dy/dt = 68 - 2(1.86)t

= 68 - 3.72t

(a) dy/dt = 68 - 3.72t

(b) To estimate the speed when t = 1, we substitute t = 1 in dy/dt .

dy/dt at t = 1 is

68 - 3.72(1)

= 68 - 3.72

= 64.28

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X²+y²-6x+14y-1=0<br> and please show your work so I can learn

Eva8 [605]

Hello there,

I hope you and your family are staying safe and healthy during this winter season.

$x^2 + y^2 -6x+14y-1=0$

We need to use the Quadratic Formula*

$x =\frac{-b+\sqrt{b^2}-4ac }{2a}$ , $\frac{-b-\sqrt{b^2} -4ac }{2a}$

Thus, given the problem:

$a = 1, b=-6, c=y^2+14y-1$

So now we just need to plug them in the Quadratic Formula*

$x=\frac{6+2\sqrt{(-6)^2-4(y^2+14y-1)} }{2}$ , $x=\frac{6-\sqrt{(-6)^2-4(y^2+14y-1)} }{2}$

As you can see, it is a mess right now. Therefore, we need to simplify it

$x=\frac{6+2\sqrt{10-y^2-14y} }{2}$ , $x = \frac{6-2\sqrt{10-y^2-14y} }{2}$

Now that's get us to the final solution:

$x=3+\sqrt{10-y^2-14y}$ , $x=3-\sqrt{10-y^2-14y}$

It is my pleasure to help students like you! If you have additional questions, please let me know.

Take care!

~Garebear

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