Answer:
C.h=infinitely many solution
Falling at the rate of 2.5 m/s for 45 seconds, the anchor fell
(2.5 m/s) x (45 s) = 112.5 meters .
If it wound up only 40 meters underwater, then it must have fallen
(112.5 m - 40 m) = 72.5 meters
from its storage position on the big cruise ship,
before it ever reached the water.
Since it was falling at the rate of 2.5 m/s, it took
(72.5 m) / (2.5 m/s) = 29 seconds
to get down to the water surface after it started dropping.
Answer:
1. 60000.12
2. 54000.15
3. 9600.48
4. 3840.48
Step-by-step explanation:
I really hope this helps and may I receive brainliest please
Answer:
259200 seconds
The conversion factor from days to seconds is 86400, which means that 1 day is equal to 86400 seconds:
1 d = 86400 s
To convert 3 days into seconds we have to multiply 3 by the conversion factor in order to get the time amount from days to seconds. We can also form a simple proportion to calculate the result:
1 d → 86400 s
3 d → T(s)
Solve the above proportion to obtain the time T in seconds:
T(s) = 3 d × 86400 s
T(s) = 259200 s
The final result is:
3 d → 259200 s
We conclude that 3 days is equivalent to 259200 seconds:
3 days = 259200 seconds
<em><u>Hope this helps :)</u></em>
Answer:
(2, 1)
Step-by-step explanation:
The best way to do this to avoid tedious fractions is to use the addition method (sometimes called the elimination method). We will work to eliminate one of the variables. Since the y values are smaller, let's work to get rid of those. That means we have to have a positive and a negative of the same number so they cancel each other out. We have a 2y and a 3y. The LCM of those numbers is 6, so we will multiply the first equation by a 3 and the second one by a 2. BUT they have to cancel out, so one of those multipliers will have to be negative. I made the 2 negative. Multiplying in the 3 and the -2:
3(-9x + 2y = -16)--> -27x + 6y = -48
-2(19x + 3y = 41)--> -38x - 6y = -82
Now you can see that the 6y and the -6y cancel each other out, leaving us to do the addition of what's left:
-65x = -130 so
x = 2
Now we will go back to either one of the original equations and sub in a 2 for x to solve for y:
19(2) + 3y = 41 so
38 + 3y = 41 and
3y = 3. Therefore,
y = 1
The solution set then is (2, 1)
