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VladimirAG [237]
3 years ago
7

Find the horizontal or oblique asymptote of f(x) = negative 3 x squared plus 7 x plus 1, all over x minus 2

Mathematics
1 answer:
leonid [27]3 years ago
3 0
When you perform the indicated division, you get
\dfrac{-3x^2+7x+1}{x-2}=-3x+1+\dfrac{3}{x-2}

The "quotient" part of this result is the oblique asymptote:
  y = -3x +1

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