3 years ago

Find the horizontal or oblique asymptote of f(x) = negative 3 x squared plus 7 x plus 1, all over x minus 2

1 answer:

3 0

When you perform the indicated division, you get
$\dfrac{-3x^2+7x+1}{x-2}=-3x+1+\dfrac{3}{x-2}$

The "quotient" part of this result is the oblique asymptote:
y = -3x +1

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